Answer:
what are you talking BOUT?
Step-by-step explanation:
Answer:
Probability that the respondent has a pet given that the respondent has had a pet is
or 0.46.
Step-by-step explanation:
We are given the following results below;
37% have a pet now and have had a pet.
63% do not have a pet now.
81% have had a pet.
19% do not have a pet now and have never had a pet.
Let event B = respondent has a pet now
Now, Probability that the respondent has had a pet = P(A) = 0.81
Probability that the respondent has a pet now and has had a pet =
= 0.37
So, Probability that the respondent has a pet given that the respondent has had a pet is given by = P(B/A)
<u>This conditional probability is solved as ;</u>
P(B/A) =
=
= 0.46.
The answer is y ≤ 8
put dot/closed circle on 8 then draw an arrow to the left all the way till 3 or pass 3 ←-----------------
This kind of problems are solved using Bernoulli's distribution. Everytime you have a win/lose scenario, and you know the probability
of winning, and you want
successes over
trials, you have the following probability:

You want the probability of having at least three successes, i.e. you are interested in the cases k=3 and k=4. The corresponding probabilities are


So, the total probability is 