Question

A gas occupies 3.60 L when the temperature is 45.0oC and at 1.02 atm of pressure. What temperature change (in K) will be needed to change the volume to 6.25 L at constant pressure?

Answer 1

As we know V1/T1=V2/T2
so,   V1=3.60
        V2=6.25
        T1=45c=318k
        T2=required
solution!
            T2=V2 multiply by T1/V1 so
   put the values and find your answer which should be 552k