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vampirchik [111]
2 years ago
8

I dont understand and this question hard well for me

Chemistry
2 answers:
Darya [45]2 years ago
5 0

Answer:

A

Explanation:

medal is a conductor so the heat will travl

Murrr4er [49]2 years ago
4 0
A
"The heat from the hot chocolate will travel to the spoon"
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Tobacco is the number one drug
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2.In a titration, 25.00 cm3 of a solution of hydrochloric acid reacted with 18.40 cm3 of sodium hydroxide solution of concentrat
telo118 [61]

Answer:

0.11mol/dm³

Explanation:

The reaction expression is given as:

             HCl   +  NaOH  →  NaCl + H₂O

Volume of acid  = 25cm³  = 0.025dm³

Volume of base  = 18.4cm³ = 0.0184dm³

Concentration of base  = 0.15mol/dm³

Solution:

The concentration of hydrochloric acid = ?

 To solve this problem, let us first find the number of moles of the base;

 Number of moles  = concentration x volume

 Number of moles  = 0.15mol/dm³ x 0.0184dm³  = 0.00276mol

From the balanced reaction equation;

          1 mole of NaOH will combine with 1 mole of HCl

Therefore,  0.00276mol of the base will combine with  0.00276mol of HCl

 So;

  Concentration of acid  = \frac{number of moles }{volume}   = \frac{ 0.00276}{0.025}   = 0.11mol/dm³

4 0
2 years ago
If you could place a piece of solid silver into a container of liquid silver, would it float or sink? Explain your answer.
8_murik_8 [283]
Liquid silver is less dense than solid silver, so the solid silver would sink
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How is steam different from water vapour
trapecia [35]
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Read 2 more answers
Fe2O3 + 2Al = 2Fe + Al2O3 is this a redox reaction
katovenus [111]

Answer:

<h3>2Al+ Fe2O3 gives 2Fe + Al2O3. The given reaction is a redox reaction. As oxidation and reduction are taking place simultaneously.</h3>

Explanation:

like this...Identify oxidation and reduction with their agents:

<h3>•2Al+ Fe2O3 →2Fe + Al2O3</h3>

<h3>•Fe2O3 is reduced to Fe whereas Al is oxidized to Al2O3</h3>

<h3>In the above reaction:</h3>

<h3>Oxidizing agent:Fe2O3</h3>

<h3>Reducing agent:Al</h3>

I hope it's help you (◠‿・)—☆

5 0
2 years ago
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