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masha68 [24]
3 years ago
9

A screen containing two slits 0.100mm apart is 1.50m from a viewing screen. Light of wavelength 633nm falls on the slits. Approx

imately how far apart are the bright fringes on the viewing screen?
Mathematics
1 answer:
Nadya [2.5K]3 years ago
7 0

Answer:

distance = 9.495 mm

Step-by-step explanation:

Given data

slits distance = 0.100 mm

viewing screen distance = 1.50 m

wavelength =  633 nm

to find out

how far apart are the bright fringes on the viewing screen

solution

we use here double slit diffraction condition that is

d sin(θ) = m λ    .......................1

here m = 0, 1 , 2 , 3   .....

and here for θ small so

sin(θ) = tan(θ) = \frac{x}{l}

so x = l sin (θ)

so from equation 1

x = \frac{m\lambda l}{d}

and

x1 =  \frac{\lambda l}{d}     ...............2

x2 =  \frac{2\lambda l}{d}   ..............3

so distance x2 - x1  will be

distance = \frac{\lambda l}{d}

distance = \frac{633*10^{-9}*1.5}{0.1*10^{-3}}

distance = 9.495 mm

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