Answer:
2Au₂S₃ + 6H₂ → 4Au + 6H₂S
Explanation:
Balancing:
2Au₂S₃ + 6H₂ → 4Au + 6H₂S
Answer:
17202.6 years
Explanation:
Activity of the living sample (Ao) = 160 counts per minute
Activity of the wood sample (A) = 20 counts per minute
Half life of carbon-14 = 5730 years
t= age of the artifact
From;
0.693/t1/2= 2.303/t log Ao/A
Then;
0.693/ 5730= 2.303/t log Ao/A
Substituting values;
0.693/5730= 2.303/t log (160/20)
Then we obtain;
1.209×10^-4 = 2.0798/t
t= 2.0798/1.209×10^-4
Thus;
t= 17202.6 years
Therefore the artifact is 17202.6 years old.
A. soluble.
The are solubility rules that predict precipitation reaction.
The Options are as follow,
<span>a.
it has 13 protons c. it has 13 neutrons </span>
<span>b.
it has 13 electrons d. it
has 7 neutrons</span>
Answer:
Option-d is the correct answer.
Explanation:
As we know that C-13 has a atomic mass of 13. Also, atomic mass is given as,
<span> Atomic Mass = # of Protons + # of Neutrons --- (1)</span>
Since;
Atomic Mass = 13
And,
# of protons = 6 (as number of protons = atomic number)
Putting values in equation 1,
13 = 6 - # of Neutrons
Solving for Number of Neutrons,
# of Neutrons = 13 - 6
# of Neutrons = 7
The answer is
(B),
Solution to your problem is as follow,
