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3 years ago

Describe in your own words, in terms of particle movement and energy, what occurs when a liquid is cooled to its freezing point.

1 answer:

4 0

Liquids have free and fast moving particles. Liquids do not take a specific shape unless they are enclosed such as in a bottle. Anyway, since they are free flowing when they freeze, their movement becomes very slow. Eventually the particles will not have room to move as they used to and will be held in one place. The particles are still moving but they are only shaking or vibrating in the same place. You can't even tell this movement is happening, and that is what happens when liquid freezes.

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Which of the following is not a catalyst? A. Nickel B. Platinum C. Enzymes D. Phosphorus

Mazyrski [523]

The answer would be D because from my research it's the only one that didn't have a catalyst

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3 years ago

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How many moles of silicon are in 5.9 X 10 to the 24 power atoms of silicon

Dimas [21]

Answer:

9.79740949850 moles

Explanation:

1 mole = Avogardo's Number <<6.022 E 23 <<particles, atoms, etc.>>
This problem can be solved using dimensional analysis by multiplying atoms (5.9E24 atoms) by (1) mole and then dividing the number by Avogardo's number (6.022 E 23 atoms).
Note: E = * 10

Side Note: Please let me know if you need any clarifications about this!

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3 years ago

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Ca(OH)2 + 2 H2SO4 → CaSO4 + 2 H2O

Pie

Answer:

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Explanation:

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3 years ago

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How many joules of heat are required to heat 110 g of aluminum from 52.0 oC to 91.5 oC?

docker41 [41]

Answer:

We need 3910.5 joules of energy

Explanation:

Step 1: Data given

Mass of aluminium = 110 grams

Initial temperature = 52.0 °C

Final temperature = 91.5 °C

Specific heat of aluminium = 0.900 J/g°C

Step 2: Calculate energy required

Q = m*c*ΔT

⇒with Q = the energy required = TO BE DETERMINED

⇒with m = the mass of aluminium = 110 grams

⇒with c = the specific heat of aluminium = 0.900 J/g°C

⇒with ΔT = the change in temperature = T2 - T1 = 91.5 °C - 52.0 °C = 39.5 °C

Q = 110 grams * 0.900 J/g°C * 39.5

Q = 3910.5 J

We need 3910.5 joules of energy

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3 years ago

For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coeffici

Brut [27]

Question:

For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coefficient for 0.124 b HCl solution if E=0.342 V at 298 K

Answer:

The mean activity coefficient for HCl solution is 0.78.

Explanation:

Activity coefficient is defined as the ratio of any chemical activity of any substance with its molar concentration. So in an electrochemical cell, we can write activity coefficient as γ. The equation for determining the mean activity coefficient is

$E=E_{0}-0.0514 \mathrm{V} \ln \gamma$