Which descriptor applies to the circuit? A- on B- closed C- incomplete D- open

The sizes of most of the cells our bodies are about A.1micrometer

Alekssandra [29.7K]

Answer:

1Mm

Explanation:

i think this one. so it is wrong then also dont be angry with me because iam trying to help u

5 0

3 years ago

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A block lies on a horizontal frictionless surface. A horizontal force of 100 N is applied to the block giving rise to an acceler

KIM [24]

Answer:

(a) m = 33.3 kg

(b) d = 150 m

(c) vf = 30 m/s

Explanation:

Newton's second law to the block:

∑F = m*a Formula (1)

∑F : algebraic sum of the forces in Newton (N)

m : mass s (kg)

a : acceleration (m/s²)

Data

F= 100 N

a= 3.0 m/s²

(a) Calculating of the mass of the block:

We replace dta in the formula (1)

F = m*a

100 = m*3

m = 100 / 3

m = 33.3 kg

Kinematic analysis

Because the block moves with uniformly accelerated movement we apply the following formulas:

d= v₀t+ (1/2)*a*t² Formula (2)

vf= v₀+a*t Formula (3)

Where:

d:displacement in meters (m)

t : time interval in seconds (s)

v₀: initial speed in m/s

vf: final speed in m/s

a: acceleration in m/s²

Data

a= 3.0 m/s²

v₀= 0

t = 10 s

(b) Distance the block will travel if the force is applied for 10 s

We replace dta in the formula (2):

d= v₀t+ (1/2)*a*t²

d = 0+ (1/2)*(3)*(10)²

d =150 m

(c) Calculate the speed of the block after the force has been applied for 10 s

We replace dta in the formula (3):

vf= v₀+a*t

vf= 0+(3*(10)

vf= 30 m/s

4 0

3 years ago

Which winds are affected by specific landforms on earth's surface?

Blababa [14]

Hello!

The winds affected by specific landforms on earth's surface are: Local winds.

I hope my answer helped you out! :)

4 0

3 years ago

Which type of wave is not a light wave

AlekseyPX

A. RED WAVES IS NOT A LIGHT WAVE BECAUSE THERE IS NOT RED WAVE.

ALSO IF YOU DONT BELIEVE SEARCH IT FROM GOOGLE

4 0

3 years ago

A centrifuge in a forensics laboratory rotates at an angular speed of 3,700 rev/min. When switched off, it rotates 46.0 times be

ra1l [238]

Answer:

Explanation:

Given,

initial angular speed, ω = 3,700 rev/min

= $3700\times \dfrac{2\pi}{60}=387.27\ rad/s$

final angular speed = 0 rad/s

Number of time it rotates= 46 times

angular displacement, θ = 2π x 46 = 92 π

Angular acceleration

$\alpha = \dfrac{\omega_f^2 - \omega^2}{2\theta}$

$\alpha = \dfrac{0 - 387.27^2}{2\times 92\ pi}$

$\alpha = -259.28 rad/s^2$

3 0

3 years ago