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lina2011 [118]
3 years ago
9

Which descriptor applies to the circuit? A- on B- closed C- incomplete D- open

Physics
2 answers:
gayaneshka [121]3 years ago
8 0
Answer is D- open.hope you get it
HACTEHA [7]3 years ago
3 0
Open circuit is the answer
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Discuss 4 way a scienicst can.reduce bias
Yanka [14]
Make sure to thank me

The answers are by:

Investigation
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7 0
4 years ago
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Pls help A ball rolls horizontally off a 100-meter-tall cliff at 40 meters per second. How far does the ball travel horizontally
svet-max [94.6K]

First find the time it takes for the ball to reach the ground using the vertical component of its position vector:

y=y_0+v_{0y}t+\dfrac12a_yt^2

\implies0=100\,\mathrm m+\dfrac12\left(-9.8\,\dfrac{\mathrm m}{\mathrm s^2}\right)t^2

\implies t=4.52\,\mathrm s

Meanwhile, the horizontal component of the ball's position vector is

x=x_0+v_{0x}t+\dfrac12a_xt^2

\implies x=\left(40\,\dfrac{\mathrm m}{\mathrm s}\right)t

After about 4.52 s, the ball has traveled a horizontal distance of

x=\left(40\,\dfrac{\mathrm m}{\mathrm s}\right)(4.52\,\mathrm s)=180.8\,\mathrm m

which you would round to 200 m, so the answer is B.

8 0
3 years ago
Practice
marshall27 [118]

Answer:

In both cases the height is greater than 10.3 m

Explanation:

Pressure is defined by the relationship

       P = F / A

in this case the force is the weight of the two gases

       F = W = m g

If we use the definition of density

      ρ = m / V

      V = A h

      m = ρ A h

we substitute

       P = ρ g h

       h = \frac{P}{\rho g}

For this case the density of the gases is

       ρ' = 0.9 \rho_{water}

       h =\frac{P}{0.9 \ \rho_{water} g}

we calculate

     ρ’= 0.9 \rho_{water}

     h = 1 105 / (0.9 1000 9.8)

     h = 11.3 m

      ρ’= 0.8 \rho_{water}

       h = 1 105 / (0.8 1000 9.8

       h = 12.8 m

In both cases the height is greater than 10.3 m

4 0
3 years ago
An object with a mass of 2.00 kg is placed at the end of a spring, having a spring constant of 180.0 N/m. The spring is then com
s2008m [1.1K]

Answer:

the velocity of the mass is 8.44 m/s

Explanation:

Given;

mass of the object, m = 2 kg

spring constant, k = 180 N/m

extension of the spring, x = 0.89 m

The maximum velocity of the mass is calculated as follows;

By the principle of conservation of energy;

Elastic potential energy = kinetic potential energy

¹/₂kx² = ¹/₂mv²

kx² = mv²

v^2 = \frac{kx^2}{m} \\\\v = \sqrt{\frac{kx^2}{m} } \\\\v = \sqrt{\frac{180 \times 0.89^2}{2} }\\\\v = 8.44 \ m/s

Therefore, the velocity of the mass is 8.44 m/s

8 0
3 years ago
At a particular instant, a stationary observer on the ground sees a package falling with speed v1 at an angle to the vertical. t
Lerok [7]
V1 * sin(θ) where θ is the angle v1 makes with the vertical.
7 0
4 years ago
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