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The answers are by:
Investigation
Sampling
Repetition
Blind Studies
First find the time it takes for the ball to reach the ground using the vertical component of its position vector:



Meanwhile, the horizontal component of the ball's position vector is


After about 4.52 s, the ball has traveled a horizontal distance of

which you would round to 200 m, so the answer is B.
Answer:
In both cases the height is greater than 10.3 m
Explanation:
Pressure is defined by the relationship
P = F / A
in this case the force is the weight of the two gases
F = W = m g
If we use the definition of density
ρ = m / V
V = A h
m = ρ A h
we substitute
P = ρ g h
h = 
For this case the density of the gases is
ρ' = 0.9
h =
we calculate
ρ’= 0.9 \rho_{water}
h = 1 105 / (0.9 1000 9.8)
h = 11.3 m
ρ’= 0.8 \rho_{water}
h = 1 105 / (0.8 1000 9.8
h = 12.8 m
In both cases the height is greater than 10.3 m
Answer:
the velocity of the mass is 8.44 m/s
Explanation:
Given;
mass of the object, m = 2 kg
spring constant, k = 180 N/m
extension of the spring, x = 0.89 m
The maximum velocity of the mass is calculated as follows;
By the principle of conservation of energy;
Elastic potential energy = kinetic potential energy
¹/₂kx² = ¹/₂mv²
kx² = mv²

Therefore, the velocity of the mass is 8.44 m/s
V1 * sin(θ) where θ is the angle v1 makes with the vertical.