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Mamont248 [21]
2 years ago
7

The batteries of some flashlights can be charged by turning a handle. Which energy transformation is happening in this process

Physics
1 answer:
s344n2d4d5 [400]2 years ago
4 0

The energy transformation that is happening in this process is mechanical energy to chemical energy.

<h3>Energy Conversion</h3>

According to conservation of energy, energy can not be distroyed and cannot be created, but can only be transformed from one form to another.

The batteries of some flashlights can be charged by turning a handle. The energy transformation that is happening in this process is mechanical energy to chemical energy. The chemical energy will transform to electrical energy which will eventually transform to light energy.

The turning of the handle is mechanical and the energy in battery is chemical.

Learn more about Energy here: brainly.com/question/25959744

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The index of refraction of light varies from color to color. TRUE.
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A student is pushing a box across the room. To push the box three times farther, the student needs to do how much work?
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Removing some of the books reduced the mass of the box, and less force was needed to push it across the floor.

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In this dark-colored forest, you started with 50% light moths and 50% dark moths. At the end of your simulation, was there a hig
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A block of mass M is connected by a string and pulley to a hanging mass m. The coefficient of kinetic friction between block M a
aleksklad [387]

Answer:

a)  y = 0.98 t², t=1s y= 0.98 m,  

b) he two blocks must move the same distance

c) v = 1.96 m / s,  d)  a = -1.96 m / s², e)  x = 0.98 m

Explanation:

For this exercise we can use Newton's second law

Big Block

Y axis

             N-W = 0

             N = M g

X axis

             T- fr = Ma

the friction force has the expression

             fr = μ N

             fr = μ Mg

small block

             w- T = m a

             

we write the system of equations

             T - fr = M a

             mg - T = m a

we add and resolved

             mg-  μ Mg = (M + m) a

             a = g \ \frac{m - \mu M}{m+M}

             a = 9.8 \ \frac{10- 0.2 \ 20}{ 10 \ +\ 20}

             a = 9.8 (6/30)

             a = 1.96 m / s²

a) now we can use the kinematic relations

             y = v₀ t + ½ a t²

the blocks come out of rest so their initial velocity is zero

             y = ½ a t²

             y = ½ 1.96 t²

             y = 0.98 t²

for t = 1s y = 0.98 m

       t = 2s y = 1.96 m

b) Time is a scale that is the same for the entire system, the question should be oriented to how far the big block will move.

As the curda is in tension the two blocks must move the same distance

c) the velocity of the block M

           v = vo + a t

           v = 0 + 1.96 t

for t = 1 s v = 1.96 m / s

       t = 2 s v = 3.92 m / s

d) the deceleration if the chain is cut

when removing the chain the tension becomes zero

           -fr = M a

          - μ M g = M a

          a = - μ g

          a = - 0.2 9.8

          a = -1.96 m / s²

e) the distance to stop the block is

         v² = vo² - 2 a x

        0 = vo² - 2a x

        x = vo² / 2a

        x = 1.96² / 2 1.96

        x = 0.98 m

the time to travel this distance is

        v = vo - a t

        t = vo / a

        t = 1.96 /1.96

        t = 1 s

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Answer:

The correct answer is All of the above.

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