A)
At time = .003 hr
B)
90* (3*10^-3) = .27km
C)
.005 hr
D)
Car A = 150 * (.005) = .75km
Car B = (90 * (.005) = .45 km
E)
Car A = 150 * (0.008) = 1.2 km
Car B = 90 * (0.008) = 0.72 km
Car A is ahead
The most dense thing inside the column is the little star. It's pink, and it's resting on the bottom of the cylinder.
The red part under the star is the solid base that the cylinder is standing in. It's probably wood or plastic, it's not free to move, and it's not involved in the experiment.
Answer:
approximately 35,786 km
Explanation:
A satellite in such an orbit is at an altitude of approximately 35,786 km (22,236 mi) above mean sea level. It maintains the same position relative to the Earth's surface.
Initial kinetic energy = 0J (v=0 (rest))
Final kinetic energy = 1/2mv ²
Ek=1/2(9)(27 ²)
Ek=4.5(729)
Ek=3280.5
∆Energy=3280.5J
(As it starts from 0)
Work= ∆energy
So work =3280.5J
Answer=3300J (forth option)
