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Vera_Pavlovna [14]
3 years ago
13

mr. Rose asked his student to draw a quadrilateral with four unequal sides. An example of this kind of quadrilateral

Chemistry
1 answer:
777dan777 [17]3 years ago
8 0
Think of w shape with 4 sides the shape I know tat is Quadrilateral is a square
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True or false Nitrogen - 15 has 7 neutrons
BaLLatris [955]

Answer:

Yes Nitrogen has 7 Neutrons

Explanation:

3 0
3 years ago
Is precipitate in water an electrolyte solution
vagabundo [1.1K]
When no ions are produced, or the ion content is low, the solute is a non-electrolyte. Non-electrolytes do not conduct electricity or conduct it to a very small degree. In an aqueous solution a strong electrolyte is considered to be completely ionized, or dissociated, in water, meaning it is soluble
4 0
3 years ago
What is the first step in the scientific method? A. form a hypothesis B. illustrate the process C. observe and ask questions D.
Tom [10]
The answer would be C) Observe and ask questions because if we do process of elimination we see that drawing conclusions is NOT the first step, forming a hypothesis and illustrating the process is part of the method, but NOT the first step.
3 0
3 years ago
Read 2 more answers
Two different proteins X and Y are dissolved in aqueous solution at 37 °C. The proteins bind in a 1:1 ratio to form XY. A soluti
aleksklad [387]

Answer:

Kc of reaction is 20.

Explanation:

The two proteins are X and Y.

The [X] = 1mM

[Y]=1mM

At equilibrium, [X] = 0.2mM  [Y] = 0.2mM

we know that equilibrium constant is:

Kc=\frac{[Products]}{[Reactants]}=\frac{[XY]}{[X][Y]}

[XY]= 1-0.20=0.80 mM

putting values:

Kc=\frac{0.80}{0.20X0.20}=20

8 0
3 years ago
A piece of copper alloy with a mass of 85.0 g is heated from 30. °C to 45 °C. In the process, it absorbs 523 J of energy as heat
Ne4ueva [31]

Answer:

410.196 J/[kg*°C].

Explanation:

1) the equation of the energy is: E=c*m*(t₂-t₁), where E - energy (523 J), c - unknown specific heat of copper, m - mass of this copper [kg], t₂ - the final temperature, t₁ - initial temerature;

2) the specific heat of copper is:

c=\frac{E}{m*(t_2-t_1)}; \ => \ c=\frac{523}{0.085*(45-30)}=\frac{523}{1.275}=410.196[\frac{J}{kg*C}].

6 0
3 years ago
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