Answer:
The independent Variable is Time, and the dependent variable is Distance
Step-by-step explanation:
Answer:
We do not reject the null
Step-by-step explanation:
Given that :
Sample size, n = 41
Test statistic ; Zstatistic ;= 1.53
Critical value ; Zcritical ; = 2.57
The null hypothesis H0 ;
H0: μ1 - μ2 = 0
Alternative hypothesis, H1 ;
H1: μ1 ≠ μ2
Decision region :
Reject Null ; if |Zstatistic ≥ Zcritical|
Zstatistic > Zcritical
Result :
1.53 < 2.57
Zstatistic < Zcritical
Hence, we do not reject the null ; there is no significant evidence that there is difference in the average yield of the two samples.
Answer:
See below.
Step-by-step explanation:
I will assume that 3n is the last term.
First let n = k, then:
Sum ( k terms) = 7k^2 + 3k
Now, the sum of k+1 terms = 7k^2 + 3k + (k+1) th term
= 7k^2 + 3k + 14(k + 1) - 4
= 7k^2 + 17k + 10
Now 7(k + 1)^2 = 7k^2 +14 k + 7 so
7k^2 + 17k + 10
= 7(k + 1)^2 + 3k + 3
= 7(k + 1)^2 + 3(k + 1)
Which is the formula for the Sum of k terms with the k replaced by k + 1.
Therefore we can say if the sum formula is true for k terms then it is also true for (k + 1) terms.
But the formula is true for 1 term because 7(1)^2 + 3(1) = 10 .
So it must also be true for all subsequent( 2,3 etc) terms.
This completes the proof.
9u+39=6(u+2)
multiply 6 by u and 2
9u+39=6u+12
9u-6u=12-39
3u=-27
u=-27/3
u=-9
hope this helped :)