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Mazyrski [523]
3 years ago
13

A piece of bismuth with a mass of 4.06 g 4.06 g gains 423 J 423 J of heat. If the specific heat of bismuth is 0.123 J / ( g ° C

) 0.123 J/(g°C) , what is the change in temperature of the sample?
Physics
1 answer:
Sholpan [36]3 years ago
4 0

Answer: 846°C

Explanation:

The quantity of Heat Energy (Q) required to heat bismuth depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Given that:

Q = 423 joules

Mass of bismuth = 4.06g

C = 0.123 J/(g°C)

Φ = ?

Then, Q = MCΦ

423 J = 4.06g x 0.123 J/(g°C) x Φ

423 J = 0.5J/°C x Φ

Φ = (423J/ 0.5g°C)

Φ = 846°C

Thus, the change in temperature of the sample is 846°C

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to find i1, i2, and i3 we need to find the total current.

to find the total current, you need to find the total resistance

you're already given the total voltage, Vs

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R3 and R4 are in series so

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9 ohms is now in parallel with R2 so,

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6 ohms is in series with R1 so

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i1= 12A

so the current splits into i2 and i3 and the amount of current that flows through a branch depends on the total resistance in each branch.

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When an electron in a certain excited energy level in a one-dimensional box of length 2.00 Å makes a transition to the ground st
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2 years ago
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For vertical motion, use the following kinematics equation:

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