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gizmo_the_mogwai [7]
3 years ago
6

Why is Earth’s North Pole a geographic north pole but a south seeking pole magnetically?

Physics
1 answer:
natima [27]3 years ago
3 0

Answer:It is actually the South Magnetic pole

Explanation:The magnetic pole near earth's geographic north pole is actually the south magnetic pole. When it comes to magnets, opposites attract. This fact means that the north end of a magnet in a compass is attracted to the south magnetic pole, which lies close to the geographic north pole.

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What is harmonic motion
Tanzania [10]

Answer:  NNOOOOOOOOOOOOOOOOOOONONONO

Explanation: simple harmonic motion, in physics, repetitive movement back and forth through an equilibrium, or central, position, so that the maximum displacement on one side of this position is equal to the maximum displacement on the other side. The time interval of each complete vibration is the same. The force responsible for the motion is always directed toward the equilibrium position and is directly proportional to the distance from it. That is, F = −kx, where F is the force, x is the displacement, and k is a constant. This relation is called Hooke’s law.

A specific example of a simple harmonic oscillator is the vibration of a mass attached to a vertical spring, the other end of which is fixed in a ceiling. At the maximum displacement −x, the spring is under its greatest tension, which forces the mass upward. At the maximum displacement +x, the spring reaches its greatest compression, which forces the mass back downward again. At either position of maximum displacement, the force is greatest and is directed toward the equilibrium position, the velocity (v) of the mass is zero, its acceleration is at a maximum, and the mass changes direction. At the equilibrium position, the velocity is at its maximum and the acceleration (a) has fallen to zero. Simple harmonic motion is characterized by this changing acceleration that always is directed toward the equilibrium position and is proportional to the displacement from the equilibrium position. Furthermore, the interval of time for each complete vibration is constant and does not depend on the size of the maximum displacement. In some form, therefore, simple harmonic motion is at the heart of timekeeping.

3 0
2 years ago
An atom of calcium-48 and an atom of calcium-47 differ in
anygoal [31]
The 48 and 47 are different atomic masses, this is caused by having a different number of neutrons.
3 0
3 years ago
Read 2 more answers
Help plz I’ll mark brainliest
slavikrds [6]
Thinner at edges and its thick in the middle
3 0
3 years ago
Read 2 more answers
A pendulum is made by letting a 2.0-kg object swing at the end of a string that has a length of 2.1 m. The maximum angle the str
just olya [345]

Answer:

The speed of the object at the lowest point in its trajectory is:

v=2.34\: m/s

Explanation:

We can use the conservation of energy between the maximum point of swing and the lowest point of the pendulum.

P=K

mgh=\frac{1}{2}mv^{2} (1)

Where:

  • h is the height of the object at 30° with the vertical.
  • v is the speed at the lowest point.

We can find h using trigonometry.

h=L-Lcos(30)=L(1-cos(30))

h=2.1(1-cos(30))=0.28\: m

Now, using equation (1) we can find v.

gh=\frac{1}{2}v^{2}

2gh=v^{2}

v=\sqrt{2gh}

v=\sqrt{2(9.81)(0.28)}

v=2.34\: m/s

I hope it helps you!

8 0
3 years ago
A diode vacuum tube consists of a cathode and an anode spaced 5-mm apart. If 300 V are applied across the plates. What is the ve
Alex_Xolod [135]

Answer:

Velocity of the electron mid way = v = 6.47×10⁶ m/s  

Explanation:

Electric potential varies with distance as V(x) = C x^\frac{4}{3}

At a distance 5 mm , the constant C is evaluated.

C = V/x^\frac{4}{3}

    = 300/(0.005)^\frac{4}{3}

     = 3.50×10⁵  

Now at the mid point, x = 2.5 mm = 0.0025 m

Potential = V' = C x^\frac{4}{3}

                      = 3.50\times 10^5\times (0.0025)^\frac{4}{3}

                      = 119 V

Kinetic energy per unit charge is equal to the electric potential.

or 0.5 m v^2 = V' q

Here m is the mass of the electron and q is the charge of the electron.

m= 9.1×10⁻³¹ kg

q = 1.6×10⁻¹⁹ coulombs

⇒ v^2 = \frac{V q}{0.5 m}

⇒ v^2 = \frac{(119)(1.6\times 10⁻¹⁹)}{0.5 (9.1\times 10⁻³¹)}

⇒ v = 6.47×10⁶ m/s

⇒ Velocity of the electron mid way = v = 6.47×10⁶ m/s    

6 0
3 years ago
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