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3 years ago

Your dog eats 7/8lb of food in 4 meals. How much food does your dog eat per meal?

Mathematics

1 answer:

san4es73 [151]3 years ago

6 0

Answer:

.21875 pounds per meal.

Step-by-step explanation:

7/8 divided by 4 is .21875

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Can someone please help me with e f and g

Deffense [45]

E. the zeros of the graph is at (0,0) and (12,0) and the function is negative,
moreover, the max is (4,81), which shows how the speed goes up then down.

f.
x=t

f(t)=t²

f(x)=x²

g. is more complicated.

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3 years ago

(1,5) with a slope of -2

laiz [17]

Answer:

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3 years ago

Determine if the statement is always, sometimes or never true.

Romashka-Z-Leto [24]

Let

x--------> the measure of the adjacent interior angle

y--------> the measure of an exterior angle at the vertex of a polygon

we know that

The measure of the adjacent interior angle and the measure of an exterior angle at the vertex of a polygon are supplementary angles

$x+y=180$ °

Examples

case 1)

In a square

$x=90$ °

$y=180-90=90$ °

$x=y$

In this case

The measure of an exterior angle at the vertex of a polygon equals the measure of the adjacent interior angle

case 2)

an equilateral triangle

$x=60$ °

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$x\neq y$

In this case

The measure of an exterior angle at the vertex of a polygon is not equals the measure of the adjacent interior angle

therefore

the answer is

sometimes

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3 years ago

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alpha and beta are the zeros of the polynomial x^2 -(k +6)x +2(2k -1). Find the value of k if alpha + beta = 1/2 alpha beta(ITS

serious [3.7K]

Answer:

$k=\frac{-11}{2}$ .

Step-by-step explanation:

We are given $\alpha$ and $\beta$ are zeros of the polynomial $x^2-(k+6)x+2(2k-1)$ .

We want to find the value of $k$ if $\alpha+\beta=\frac{1}{2}$ .

Lets use veita's formula.

By that formula we have the following equations:

$\alpha+\beta=\frac{-(-(k+6))}{1}$ (-b/a where the quadratic is ax^2+bx+c)

$\alpha \cdot \beta=\frac{2(2k-1)}{1}$ (c/a)

Let's simplify those equations:

$\alpha+\beta=k+6$

$\alpha \cdot \beta=4k-2$

If $\alpha+\beta=k+6$ and $\alpha+\beta=\frac{1}{2}$ , then $k+6=\frac{1}{2}$ .

Let's solve this for k:

Subtract 6 on both sides:

$k=\frac{1}{2}-6$

Find a common denominator:

$k=\frac{1}{2}-\frac{12}{2}$

Simplify:

$k=\frac{-11}{2}$ .

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3 years ago