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wariber [46]
3 years ago
8

Which type of heat transfer can happen even if there are no particles of matter? A. Conduction B. Radiation C. Convection D. Ins

ulation
Physics
2 answers:
Ghella [55]3 years ago
6 0

Answer:

B. Radiation

Explanation:

Naddik [55]3 years ago
3 0

Heat can travel as<em> radiation</em>, even if there are no particles of matter
along the way.  Which is really lucky, because that's how we get
heat from the sun.  And light too.


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A heat pump has a coefficient of performance that is 60% of the Carnot heat pump coefficient of performance. The heat pump is us
Nataliya [291]

Answer:

T_C=118.8 K= 154.2°C

Explanation:

COP_max of carnot heat pump= \frac{T_{H} }{T_{H}-T_{C} }

where T_H and T_C are temperatures of hot and cold reservoirs

Also COP=\frac{Q_H}{W}

in the question COP= \frac{60}{100} \times COP_{max}

⇒\frac{Q_H}{W} =\frac{60}{100}\times\frac{T_H}{T_H-T_C}

heat is added directly to be as efficient as via heat pump

Q_H= W

and T_H= 24° C= 297 K

1=\frac{60}{100}\times \frac{297}{297-T_C}

on calculating the above equation we get

T_C=118.8 K

the outdoor temperature for efficient addition of heat to interior of home

T_C=118.8 K= 154.2°C

6 0
3 years ago
Using newtons second law of motion, how fast for 100 KG object accelerates 350 N of force is applied to
fenix001 [56]

Answer:

3.5m/s^2

Explanation:

From Newton's second Law of Motion

F = ma

Where F is the applied force, m is the mass of the object and a is the acceleration.

F = 350 N

Mass = 100kg

350N = 100×a

a = 350/100

a = 3.5m/s^2

The acceleration of the object will be 3.5m/s^2

6 0
3 years ago
A sample of helium gas has a volume of 900. milliliters and a pressure of 2.50 atm at 298 K. What is the new pressure when the t
Sladkaya [172]

Answer:

<em>The new pressure = 5.64 atm.</em>

Explanation:

Using The general gas equation,

P₁V₁/T₁ = P₂V₂/T₂..................... Equation 1

making P₂ the subject of the equation

P₂ = P₁V₁T₂/V₂T₁ ...................... Equation 2

Where P₁ = initial pressure, V₁ = initial Volume, T₁ = Initial temperature, P₂ = final pressure, V₂ = final volume, T₂ = final Temperature.

<em>Given: P ₁= 2.5 atm, T₁ = 298 K, V₁= 900 milliliters, T ₂= 336 K, V₂ = 450 milliliters</em>

<em>Substituting these values into equation 2,</em>

<em>P₂ = (2.5×900×336)/(298×450)</em>

P₂ = 756000/134100

P₂ = 5.64 atm.

<em>Thus the new pressure = 5.64 atm.</em>

5 0
3 years ago
How would a spinning disk's kinetic energy change if its moment of inertia was five times larger but its angular speed was five
Keith_Richards [23]

Answer:

<em>The kinetic energy of a spinning disk will be reduced to a tenth of its initial kinetic energy if its moment of inertia is made five times larger, but its angular speed is made five times smaller.</em>

<em></em>

Explanation:

Let us first consider the initial characteristics of the angular motion of the disk

moment of inertia = I

angular speed = ω

For the second case, we consider the characteristics to now be

moment of inertia = 5I  (five times larger)

angular speed = ω/5  (five times smaller)

Recall that the kinetic energy of a spinning body is given as

KE = \frac{1}{2}Iw^{2}

therefore,

for the first case, the K.E. is given as

KE = \frac{1}{2}Iw^{2}

and for the second case, the K.E. is given as

KE = \frac{1}{2}(5I)(\frac{w}{5} )^{2}   = \frac{5}{50}Iw^{2}

KE = \frac{1}{10}Iw^{2}

<em>this is one-tenth the kinetic energy before its spinning characteristics were changed.</em>

<em>This implies that the kinetic energy of the spinning disk will be reduced to a tenth of its initial kinetic energy if its moment of inertia is made five times larger, but its angular speed is made five times smaller.</em>

6 0
3 years ago
To measure one wavelength, you would measure the distance between?
makvit [3.9K]

A and B, one wavelength is crest too crest


8 0
3 years ago
Read 2 more answers
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