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ArbitrLikvidat [17]

3 years ago

6

Franklin needs to ship a box with FedEx. In order to calculate his shipping costs, he needs to measure the mass of the package.

What is the base unit that he should use in this case?
A. meter B. liter C. gram

2 answers:

balandron [24]3 years ago

8 0

Answer:

meter

Explanation:

please mark as brainlist answer

ElenaW [278]3 years ago

4 0

Gram gram gram gram gram

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Vlad1618 [11]

Answer:

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Explanation:

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3 years ago

A measurement must include both a number and a(an)

IrinaK [193]

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3 years ago

Using Rayleigh's criterion, what is the smallest separation between two pointlike objects that a person could clearly resolve at

atroni [7]

Answer:

y = 52.44 10⁻⁶ m

Explanation:

It is Rayleigh's principle that two points are resolved if the maximum of the diffraction pattern of one matches the minimum the diffraction pattern of the other

Based on this principle we must find the angle of the first minimum of the diffraction expression

a sin θ= m λ

The first minimum occurs for m = 1

sin θ = λ / a

Now let's use trigonometry the object is a distance L = 0.205 m

tan θ = y / L

Since the angles are very small, let's approximate

tan θ = sin θ/cos θ = sin θ

sin θ = y / L

We substitute in the diffraction equation

y / L = λ / a

y = λ L / a

Let's calculate

y = 550 10⁻⁹ 0.205 / 2.15 10⁻³

y = 52.44 10⁻⁶ m

7 0

4 years ago

Which variable is changed in an experiment?

Shtirlitz [24]

C. The Independent variable

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3 years ago

How much charge can be added to each of the plates before a spark jumps between the two plates? For such flat electrodes, assume

Svetach [21]

Answer:

$9.56\cdot 10^{-7} C$

Explanation:

A parallel-plate capacitors consist of two parallel plates charged with opposite charge.

Since the distance between the plates (1 cm) is very small compared to the side of the plates (19 cm), we can consider these two plates as two infinite sheets of charge.

The electric field between two infinite sheets with opposite charge is:

$E=\frac{\sigma}{\epsilon_0}$

where

$\sigma=\frac{Q}{A}$ is the surface charge density, where

Q is the charge on the plate

A is the area of the plate

$\epsilon_0 = 8.85\cdot 10^{-12}F/m$ is the vacuum permittivity

In this problem:

- The side of one plate is

L = 19 cm = 0.19 m

So the area is

$A=L^2=(0.19)^2=0.036m^2$

Here we want to find the maximum charge that can be stored on the plates such that the value of the electric field does not overcome:

$E=3\cdot 10^6 N/C$

Substituting this value into the previous formula and re-arranging it for Q, we find the charge:

$E=\frac{Q}{A\epsilon_0}\\Q=EA\epsilon_0 = (3\cdot 10^6)(0.036)(8.85\cdot 10^{-12})=9.56\cdot 10^{-7} C$

7 0

4 years ago