Answer:
The total mechanical energy of the skydiver is, E = 96402.6 J
Explanation:
Given data,
The mass of the skydiver, m = 100 kg
The speed of the skydiver at 80 m height, v = 60 m/s
The initial velocity of the skydiver, u = 0
Using the III equations of motion,
v² = u² + 2gs
s = v²/2g
Substituting the given values,
s = ½ 60²/ 9.8
= 18.37 m
Hence the initial total distance of the skydiver from the ground initially,
h = s + d
= 18.37 + 80
= 98.37 m
Since the total mechanical energy of a system is conserved, the total mechanical energy of the skydiver at height 'h' is equal to the total mechanical energy at height 'd'.
E = P.E + K.E
= mgh + ½ mu²
= 100 x 9.8 x 98.37 ( ∵ u = 0)
= 96402.6 J
Hence, the total mechanical energy of the skydiver is, E = 96402.6 J
