1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anon25 [30]
4 years ago
10

when liquid gold becomes a solid, it's particles get closer together. which best describes what happened to the gold?

Physics
2 answers:
Pepsi [2]4 years ago
5 0
I believe it’s option D. The partials get closer together

Hope this helps :)
Sergio [31]4 years ago
5 0

Answer:

D is correct answer trust me I got 100% on Edgenuity 2020

Explanation:

You might be interested in
Which statement describes a physical property related to the particles that make up a material? A. Gold ions in a piece of jewel
ohaa [14]

Answer: Metallic bonds between tin ions cause a sheet of tin to be malleable

Explanation:

4 0
3 years ago
Read 2 more answers
A roller coaster starts from rest at point A. What is its speed at point C if the track is frictionless.
OleMash [197]
At A, coaster is only associated with potential energy.
At B, coaster is associated with kinetic as well as potential energy.
Since the track is frictionless, no energy will be lost when coaster reaches from point A to point B. Therefore, according to conservation of energy, total energy at A should be equal to total energy at B.
Total energy at A = mgh = mg(12) 
Total energy at B = mgh+ mv²/2 = mg(2) + mv²/2
∴12mg = 2mg + mv²/2
∴(12g-2g)×2 = v²
∴v² = 20g
∴v = 14m/s.

Again conserving energy at points B and C.
Total energy at B = 2mg + m(14)²/2 
Total energy at C = 4mg + mv²/2
∴2mg + m(14²)/2 = 4mg + mv²/2
Solving this you get,
v = 12.52 m/s.
Therefore, speed of roller coaster at point C is 12.52 m/s.
8 0
4 years ago
The system below uses massless pulleys and ropes. The coefficient of friction is μ. Assume that M1 and M2 are sliding. Gravity i
Archy [21]

Explanation:

Using Newtons second law on each block

F = m*a

Block 1

T_{1} - u*g*M_{1} = M_{1} *a \\\\T_{1} = M_{1}*(a + u*g) ... Eq1

Block 2

T_{2} - u*g*M_{2} = M_{2} *a \\\\T_{2} = M_{2}*(a + u*g) ... Eq2

Block 3

- (T_{1} + T_{2} ) + g*M_{3} = M_{3} *a \\\\T_{1} + T_{2} = M_{3}*( -a + g) ... Eq3

Solving Eq1,2,3 simultaneously

Divide 1 and 2

\frac{T_{1} }{T_{2}} = \frac{M_{1}*(a+u*g)}{M_{2}*(a+u*g)}  \\\\\frac{T_{1} }{T_{2}} = \frac{M_{1} }{M_{2} }\\\\ T_{1} =  \frac{M_{1} *T_{2} }{M_{2} } .... Eq4

Put Eq 4 into Eq3

T_{2} = \frac{M_{3}*(g-a) }{1+\frac{M_{1} }{M_{2} } }  ...Eq5

Put Eq 5 into Eq2 and solve for a

a = \frac{M_{3}*g -u*g*(M_{1} + M_{2}) }{M_{1} + M_{2} + M_{3} }  .... Eq6

Substitute back in Eq2 and use Eq4 and solve for T2 & T1

T_{2} = M_{2}*M_{3}*g*(\frac{1-u}{M_{1} + M_{2}+M_{3}})\\\\T_{1} = M_{1}*M_{3}*g*(\frac{1-u}{M_{1} + M_{2}+M_{3}})\\\\

5 0
4 years ago
A graduated cylinder contains 62 ml of water. When a small metal block is added to the water, the volume of the water increases
lawyer [7]

Answer:

The density of the block is 7.4g/ml.

Explanation:

We can determine the volume of the metal block by taking the difference between the volumes measured in the graduated cylinder:

V_{block}=65.5ml-62ml\\\\V_{block}=3.5ml

Now, as we know that the average density of an object is calculated dividing its mass by its volume, we can calculate the density ρ of the metal block using the expression:

\rho_{block}=\frac{m_{block}}{V_{block}}\\\\\rho_{block}=\frac{26g}{3.5ml}\\\\\rho_{block}=7.4\frac{g}{ml}

Finally, it means that the density of the metal block is 7.4g/ml.

3 0
3 years ago
Read 2 more answers
A person throws a ball straight up into the air with a speed of 7.3m/s. How high does the ball go?
Colt1911 [192]

Answer:

2.6645m

Explanation:

applying motion equations we can find the answer,

v^{2}=u^{2}  +2as

Let assume ,

u = starting speed(velocity)

v = Final speed (velocity)

s =  distance traveled

a = acceleration

by the time of reaching the highest point subjected to the gravity , the speed should be equal to zero

we consider the motion upwards , in this case the gravitational acceleration should be negative in upwards (assume g =10 m/s2 downwards)

that is,

v^{2}=u^{2}  +2as\\0=7.3^{2} -2*10*s\\s=2.6645m

4 0
4 years ago
Other questions:
  • According to the graph, the volume of the gas is
    7·1 answer
  • How much work is required to stop an electron (m = 9.11 \times 10^ - 31 kg) which is moving with a speed of 2.10
    13·1 answer
  • All interactions between the atmosphere and the geosphere involve
    7·1 answer
  • We can use the textbook results for head-on elastic collisions to analyze the recoil of the Earth when a ball bounces off a wall
    11·2 answers
  • Distinguish the difference in mass and weight
    7·1 answer
  • A cat is chasing a bird across your yard. It covers 14.6 m in 2.8 s. What is its average velocity?
    14·1 answer
  • A mover pushes a 46.0kg crate 10.3m across a rough floor without acceleration. How much work did the mover do (horizontally) pus
    7·1 answer
  • You have a 40-Hz sound wave and a 5,000-Hz sound wave. Both are traveling
    14·1 answer
  • Fill in the missing words thats all but I don't know so yeah ​
    15·1 answer
  • An emergency vehicle blowing its siren is moving
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!