consider the motion in x-direction
= initial velocity in x-direction = ?
X = horizontal distance traveled = 100 m
= acceleration along x-direction = 0 m/s²
t = time of travel = 4.60 sec
Using the equation
X =
t + (0.5)
t²
100 =
(4.60)
= 21.7 m/s
consider the motion along y-direction
= initial velocity in y-direction = ?
Y = vertical displacement = 0 m
= acceleration along x-direction = - 9.8 m/s²
t = time of travel = 4.60 sec
Using the equation
Y =
t + (0.5)
t²
0 =
(4.60) + (0.5) (- 9.8) (4.60)²
= 22.54 m/s
initial velocity is given as
= sqrt((
)² + (
)²)
= sqrt((21.7)² + (22.54)²) = 31.3 m/s
direction: θ = tan⁻¹(22.54/21.7) = 46.12 deg
Answer:
2.5m/s²
Explanation:
Given parameters:
Mass of car = 200kg
Force on car = 500N
Unknown:
Acceleration of the car = ?
Solution:
According to Newton's second law of motion:
Force = mass x acceleration
Insert the given parameters and find the acceleration;
500 = 200 x acceleration
acceleration = 2.5m/s²
Answer:
A wheel and axle may either increase or decrease the input force, depending on whether the input force is applied to the axle or the wheel. ... Because the output force is less than the input force, the mechanical advantage is less than 1. However, the wheel turns over a greater distance, so it turns faster than the axle.
If you apply a force to the wheel (the handle), the wheel spins and multiplies the effort to make the output force of the axle (shaft) greater.
The drive shaft, which on most cars runs the length of the vehicle to the rear wheels, turns as the combustion engine burns gasoline. The turning drive shaft sends power to the rear axle and wheels, which cause them to turn as well, moving the car forward
There some moments when the steering wheel becomes stiff and hard to turn. From irregular servicing, lack of fluid oil to low tyre pressure or bad wheel alignment, any of these could be the cause
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Potential energy = (mass) x (gravity) x (height)
1 joule = (1,000 kg) x (9.8 m/s²) x (height)
Height = 1 joule / (9,800 newtons)
= 1/9800 meter
= 0.000102 meter
= 0.102 millimeter (rounded)
Stress = force / area
= 4.8 x 10³ / 1.2 x 10^-4
= 4 x 10⁷ N /m²
YOUNGS MODULAS = stress / strain
= 4 x 10⁷ / 1.2 x 10^11
= 3.3 x 10^-4
INCREMENT OF LENGTH = longitudinal length x intitial length
= ( 3.3 x 10^-4 ) x 4
= 13.2 x 10^-4 m
= 13.2 mm
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