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Andrej [43]
3 years ago
9

Let's begin by determining the equilibrium position of a seesaw pivot. You and a friend play on a seesaw.Your mass is____

Physics
1 answer:
expeople1 [14]3 years ago
6 0

Answer:

1.2 m from the left end

Explanation:

M = mass of the person = 90 kg

m  = mass of friend = 60 kg

r  = distance of pivot from the person or from the left end

L  = length of the seesaw board = 3.0 m

s  = distance of pivot from the friend or from right end = L - r = 3 - r

Using equilibrium of torque about the pivot

M g r = m g s\\(90) r = (60) (3 - r)\\90 r = 180 - 60 r\\90 r + 60 r = 180 \\150 r = 180 \\r = 1.2

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