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den301095 [7]
2 years ago
14

7. Kepler’s Third Law of Orbital Motion states that you can approximate the period P (in Earth years) it takes a planet to compl

ete one orbit of the sun using the function , where d is the distance (in astronomical units, AU) from the planet to the sun. How many Earth years would it take for a planet that is 6.76 AU from the sun? 15.23
17.58
154.46
3.58
Physics
2 answers:
irga5000 [103]2 years ago
8 0

In your question, this function is supposed to be in the little space after the word "function":

(square of the orbital period) = k · (cube of the distance from the sun)

' k ' is the same number for every solar-system object

To answer the question, we first have to find out what ' k ' is.  Since it's the same number for every planet in our solar system, we can find ' k ' for the Earth, and then use it for the mystery planet.

Period = 1 Earth year

Distance = 1 Astronomical unit

P² = k · D³

1² = k · 1³

k = 1  

Now for the mystery planet:  

P² = k · D³

P² = 1 · (6.76)³

P² = 308.9 Earth years²

P = √308.9

<em>P = 17.58 Earth years</em>

Angelina_Jolie [31]2 years ago
4 0

Answer: The planet will take 17.58 earth years

Explanation:

Mass of the sun = 1 Solar

Time period  of planet = T

Distance between the earth and planet = 6.67 AU

G = gravitation constant = 39.478 AU^3 y^{-2} MS^{-1}

Using Kepler's third law:

T^2=\frac{4\pi^2}{G M_{sun}}\times r^3

T^2=\frac{4\times 3.14\times 3.14}{39.478 AU^3 y^{-2} MS^{-1}\times 1 MS}\times (6.76 AU)^3

T^2=308.605 y^2

T = 17.567156 years

The closest answer from the option is 17.58 years

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Answer:

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Explanation:

Given that,

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According to Newton's third law, when object 1 exerts a force on an object 2, then object 2 will exert a force on object 1 but in opposite direction.

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4 0
2 years ago
A 100 kg person rides in an elevator moving at a constant speed of
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Answer:

Explanation:

All this information only applies to the person. There is an extra tension force if we are talking about the elevator, but we are not. Dont forget to apply the units

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The forces ONLY acting on the person would be the force of gravity pulling them down, and the normal force that the elevator is reciprocating from the person standing on it.

Force = mass x acceleration. You have 100 kg and you are accelerating at 0 m/s. The force is 0. Which makes sense because the force of gravity and the net force completely cancel each other out.

8 0
3 years ago
You stand on a straight desert road at night and observe a vehicle approaching. This vehicle is equipped with two small headligh
spayn [35]

To solve this problem we will apply the concepts related to Reyleigh's criteria. Here the resolution of the eye is defined as 1.22 times the wavelength over the diameter of the eye. Mathematically this is,

\theta = \frac{1.22 \lambda }{D}

Here,

D is diameter of the eye

D = \frac{1.22 (539nm)}{5.11 mm}

D= 1.287*10^{-4}m

The angle that relates the distance between the lights and the distance to the lamp is given by,

Sin\theta = \frac{d}{L}

For small angle, sin\theta = \theta

sin \theta = \frac{d}{L}

Here,

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For small angle sin \theta = \theta

Therefore,

L = \frac{d}{sin\theta}

L = \frac{0.691m}{1.287*10^{-4}}

L = 5367m

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4 0
3 years ago
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Answer:

Explanation:

Using the formula for calculating range expressed as;

R = U√2H/g

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Substitute into the fromula;

R = 300√2(78.4)/9.8

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3 0
3 years ago
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Crazy boy [7]

Answer:

Usually the coefficient of friction remains unchanged

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Plus, the coefficient of friction is a property of the materials being "rubbed", and this property usually does not depend on the normal force.

6 0
3 years ago
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