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Tpy6a [65]
3 years ago
10

Mature elephants consume an average of 600 pounds of food per day. If an elephant

Chemistry
1 answer:
MAXImum [283]3 years ago
5 0

Answer:

\large \boxed{\text{4 600 000 kg or 4600 Mg}}

Explanation:

1. Calculate the adult life

If the elephant is an adult from its 10th birthday until the day before its 56th birthday, its  

Adult life = 55 - 10 + 1 = 46 yr

2. Convert years to days

\text{Adult life} = \text{46 yr} \times \dfrac{\text{365.25 da}}{\text{1 yr}} = \text{16 800 da}

3. Convert days to pounds of feed

\text{Feed} = \text{16 800 da} \times \dfrac{\text{600 lb}}{\text{1 da}} = 1.01 \times 10^{7} \text{ lb}

4. Convert pounds to kilograms and megagrams

\text{Feed} =1.01 \times 10^{7} \text{ lb} \times \dfrac{\text{1 kg}}{\text{2.20 lb}} =\textbf{4 600 000 kg} = \textbf{4600 Mg}\\\\\text{The elephant will eat $\large \boxed{\textbf{4 600 000 kg or 4600 Mg}}$ of food.}

Note: The answer can have only two significant figures because that is all you gave for age of the elephant.

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Calculate the speed of light in water. The speed of light in air is 3.00 x 108 m/s.
xz_007 [3.2K]

Answer:

225,563,910 m/s

Explanation:

speed of light in water = speed of light in the air/refractive index

speed of light in water = 3.00 x 10^8 m/s/1.33

speed of light in water = 225,563,910 m/s

4 0
2 years ago
1. a) Anthony and Joseph create a start up company to make batteries for electric cars. Iron(III) phosphate is needed to create
Elenna [48]

Answer:

 LR is Na₃PO₄  

Explanation:

A quick way to determine the limiting reactant in a process is to convert reactant values to moles and then divide by the respective coefficient of the balanced equation. The smaller number of the division is the limiting reactant. For the given reaction, the rxn ratio of reactants is 1:1 so only the smaller mole value gives limiting reactant. However, if the reaction is NOT 1:1 the one must divide by respective coefficient to identify the smallest value and the limiting reactant.

This problem:

                          FeCl3(aq)          +    Na3PO4(aq)   => FePO4(s) + 3 NaCl(aq)

Given:                  27.8g                          61.9g

moles:        27.8g/162.2g/mole      1.9g/163.94g/mole

                    = 0.1714 mole               = 0.0116 mole

÷ coef.         => 0.1714/1 = 0.1714      => 0.0116/1 = 0.0116

smaller value is LR => =>  =>  =>  => => LR is Na₃PO₄              

Hope this helps. Doc :-)    

3 0
3 years ago
When a cold front passes, the air temperature should begin to rise true or false?
sleet_krkn [62]
False the opposite should happen!
7 0
2 years ago
Read 2 more answers
What is electroluminescence? Give one example.​
vredina [299]

Answer:

electroluminescence is a production of light by the flow of electrons, as within certain crystals. An example is at most resataurants with a bright sign that either says open or closed.

Explanation:

5 0
3 years ago
For water at 30C and 1 atm: a= 3.04x10^-4 k^-1 , k =4.52x10^-5 atm ^-1 = 4.46 x10^-10 m^2/N, cpm= 75.3j/9molk), Vm =18.1cm^3/mol
Lapatulllka [165]

Answer:

C_{vm} of water at 30C and 1 atm is 256.834 J/mol·K.

Explanation:

To solve the question, we note the Maxwell relation such as

C_{pm}-C_{vm}=\frac{9T\alpha ^2 V }{K}

Where:

C_{pm} = Specific heat of gas at constant pressure = 75.3 J/mol·K

C_{vm} = Specific heat of gas at constant volume = Required

T = Temperature = 30 °C = 303.15 K

α = Linear expansion coefficient = 3.04 × 10⁻⁴ K⁻¹

K = Volume comprehensibility = 4.52 × 10⁻⁵ atm⁻¹

Therefore,

75.3 - C_v = \frac{9\times 303.15 \times (3.04 \times 10^{-1} 1.81  \times 10^{-5}  }{4.52 \times 10^{-5} }

C_{vm}  = \frac{9\times 303.15 \times (3.04 \times 10^{-1} 1.81  \times 10^{-5}  }{4.52 \times 10^{-5} } - 75.3 = 256.834 J/mol·K.

8 0
3 years ago
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