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ch4aika [34]
3 years ago
5

a sample that has a half life of 45 years take ____ for the count rate to drop from 600 cpm to 150 cpm

Chemistry
1 answer:
Bond [772]3 years ago
5 0

Answer:

90yrs

Explanation:

Half life is the time taken for half of an original radioactive material to decay by half.

For the sample;

    Half - life = 45yrs

  Original amount  = 600cpm

 

                 Start                                  Number of atoms    

                 0yrs                                                600cpm

                                   First half life

                 45yrs                                              300cpm

                                  Second half life

                 90yrs                                               150cpm

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Cuales son las propiedades de la materia
lubasha [3.4K]

Answer:]

Las propiedades de la materia incluyen cualquier rasgo que se pueda medir, como la densidad, el color, la masa, el volumen, la longitud, la maleabilidad, el punto de fusión, la dureza, el olor, la temperatura y más de un objeto

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What is the pH of a solution formed at the neutralization point by the reaction of 25.0 mL of 0.180 molar acetic acid (Ka = 1.8
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3 years ago
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pav-90 [236]
<h3>Answer:</h3>

388.94 g N₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Stoichiometry
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN]   4HCl (g) + 6NO (g) → 5N₂ (g) + 6H₂O (g)

[Given]   404.87 g HCl

<u>Step 2: Identify Conversions</u>

[RxN]   4 mol HCl = 5 mol N₂

Molar Mass of H - 1.01 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of HCl - 1.01 + 35.45 = 36.46 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of N₂ - 2(14.01) = 28.02 g/mol

<u>Step 3: Stoichiometry</u>

<u />404.87 \ g \ HCl(\frac{1 \ mol \ HCl}{36.46 \ g \ HCl} )(\frac{5 \ mol \ N_2}{4 \ mol \ HCl} )(\frac{28.02 \ g \ N_2}{1 \ mol \ N_2} ) = 388.935 g N₂

<u>Step 4: Check</u>

<em>We are given 5 sig figs. Follow sig fig rules and round.</em>

388.935 g N₂ ≈ 388.94 g N₂

4 0
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klasskru [66]
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6 0
3 years ago
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