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san4es73 [151]
2 years ago
6

7. Allicin, C6H65,0, is the compound that gives garlic its odor. A sample of allicin contains 3.0 X 1021 atoms of carbon. How ma

ny hydrogen atoms does this sample contain? (A) 10 (C) 1.8 X 10^21 (B) 1.0 X 10^21 (D) 5.0 X 10^21
I know the answer is 5.0 X 10^21, but I don't know how to calculate it.​
Chemistry
1 answer:
Leona [35]2 years ago
4 0
N(C): N(H)=n(C): n(H)=6: 10
3×10²¹: x=6: 10
x=5×10²¹
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(5points) Na2[Fe(OH2)2(OH)I3]absorbs photons with energy of 191kJ/mol. Calculate the wavelength (in nm) for a photon absorbed by
AfilCa [17]

Answer:

626.7nm

Explanation:

The energy of a photon is defined as:

E = hc / λ

<em>Where E is the energy of the photon, h is Planck constant (6.626x10⁻³⁴Js), c is speed of light (3x10⁸m/s) and </em>λ is the wavelength of light

The energy of 1 photon is:

(191000 J / mol) ₓ (1 mole / 6.022x10²³) = 3.1717x10⁻¹⁹ J

Replacing:

3.1717x10⁻¹⁹ J = <em>6.626x10⁻³⁴Jsₓ3x10⁸m/s /  </em>λ

λ = 6.267x10⁻⁷m

as 1nm = 1x10⁻⁹m:

6.267x10⁻⁷m ₓ (1nm / 1x10⁻⁹m) =

<h3>626.7nm</h3>
6 0
4 years ago
How can you chose values for x when making a table of values representing a real world situation?
Nitella [24]
X is usually representing time so years, days, etc
7 0
3 years ago
Which of the following is an example of a compound? A. helium B. water C. hydrogen B. oxygen
liq [111]

the compound is B.

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7 0
3 years ago
Read 2 more answers
If the initial volume is 55ml and the final volume after some rocks of sandstone are added is 65ml what is the volume of the chi
AfilCa [17]

Answer:

Volume = 10ml

Density = 1/5 g/ml or 0.20g/ml

Explanation:

The rocks are 10ml since the initial volume went up by 10.

Since density = mass/volume, you divide 2 by 10.

D = 2/10

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7 0
3 years ago
What would be the mass of 9.03*10^21 molecules of hydrobromic acid
Fynjy0 [20]

Answer:

2.11 g hydrobromic acid (correct to 3SF)

Explanation:

Molecular formula of hydrobromic acid = C2H5BrO2

mass of C2H5BrO2 = 140.96g

Beginning with what we're given, 9.03*10^21 we then make a conversion by using Avegadro's number which is 6.02*10^23 per mole (Oct. 23 at 6:02 am is national mole day :) Then, we need to convert out of moles, 140.96g hydrombromic acid per mole.

It looks like this:

9.03*10^21 molecules • (1 mol C2H5BrO2 / 6.02*10^23 molecules) • (140g C2H5BrO2 / 1 mol) = 2.1144 g C2H5BrO2

3 0
3 years ago
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