All categories

3 years ago

Which of the following materials would you use as the metallic core of an electromagnet?

Chemistry

2 answers:

Ivanshal [37]3 years ago

7 0

Answer: The correct answer is "iron nail".

Explanation:

Electromagnet: It is a temporary magnet. It consists of iron core wounded by the coils and then the current is passed through it.

Then, it will act as a magnet as long as the current is passed through it. When the current flows through it then the electromagnet becomes active.

It loses its magnetism when the power is switched off.

Iron inside the coil makes the magnetic field stronger. It becomes magnetized when the current flows through it. It is used in the electromagnet as it loses its magnetism when the current stops flowing through it.

From the given options in the problem, Only the iron nail can be used as the metallic core of an electromagnet.

melomori [17]3 years ago

6 0

The nails would be used as they're made of iron:)

You might be interested in

Suppose of sodium chloride is dissolved in of a aqueous solution of ammonium sulfate. Calculate the final molarity of sodium cat

mariarad [96]

Answer:

0.103 M.

Explanation:

The balanced equation of reaction is given below;

2NaCl + (NH4)2SO4 -----------------> Na2SO4 + 2NH4Cl

The parameters given from the question are; mass of Sodium chloride, NaCl = 0.197 g, the volume of ammonium sulphate is 100 mL = 0.1 litres, concentration of ammonium sulfate = 54.0mM = 0.054 mol/L.

Step one: Calculate the number of moles of NaCl by using the formula below;

Number of moles,n= mass/ mass number.

Number of moles,n = 0.917/ 58.5.

Number of moles, n= 0.0157 g/mol.

Step two: find the number of moles of ammonium sulfate.

Hence, the number of moles of ammonium sulfate, n = concentration (mol/L) of ammonium sulfate × volume.

Therefore, the number of moles of ammonium sulfate, n = 0.054 × 0.1.

the number of moles of ammonium sulfate, n = 0.0054 mol.

Step three: Calculate the excess moles of NaCl.

That is; 0.0157 - 0.0054 = 0.0103 mol.

Step four: Calculate the final molarity of sodium cation in the solution.

[Na^+] = number of moles/ total volume.

[Na^+] = 0.0103 mol/ 0.1.

0.0103 mol= 0.103 M.

5 0

3 years ago

you are exploring the properties of a piece of matter you cut it in half several times which property of matter changes

Lapatulllka [165]

Only Extensive properties of piece will be changed. i.e Mass, Volume, Length etc.

3 0

3 years ago

Why does a transformer require AC rather than DC?

LuckyWell [14K]

So if the voltage in case of DC is same as AC, then DC current is larger than ACcurrent. A transformer works on the principle of electromagnetic induction. It means that the change in magnetic flux across a coil induces a potential difference across the same.

Hope this sorta helps! I'm new to this!

5 0

3 years ago

Read 2 more answers

What is the freezing point of a solution of 465 g of sucrose c12h22o11 dissolved in 575 ml of water?

Amanda [17]

Answer:

The freezing point of the solution is - 4.39 °C.

Explanation:

We can solve this problem using the relation:

ΔTf = (Kf)(m),

where, ΔTf is the depression in the freezing point.

Kf is the molal freezing point depression constant of water = -1.86 °C/m,

density of water = 1 g/mL.

So, the mass of 575 mL is 575 g = 0.575 kg.

m is the molality of the solution (m = moles of solute / kg of solvent = (465 g / 342.3 g/mol)/(0.575 kg) = 2.36 m.

∴ ΔTf = (Kf)(m) = (-1.86 °C/m)(2.36 m) = - 4.39 °C.

∵ The freezing point if water is 0.0 °C and it is depressed by - 4.39 °C.

∴ The freezing point of the solution is - 4.39 °C.

6 0

3 years ago

What is the difference between a positive and negative ion?

ra1l [238]

Positive ions or molecules that have lost one or more electrons where negative ions are actually oxygen atoms with extra negatively charged electrons.

5 0

3 years ago