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scZoUnD [109]
3 years ago
14

Which of the following materials would you use as the metallic core of an electromagnet?

Chemistry
2 answers:
Ivanshal [37]3 years ago
7 0

Answer: The correct answer is "iron nail".

Explanation:

Electromagnet: It is a temporary magnet. It consists of iron core wounded by the coils and then the current is passed through it.

Then, it will act as a magnet as long as the current is passed through it. When the current flows through it then the electromagnet becomes active.

It loses its magnetism when the power is switched off.

Iron inside the coil makes the magnetic field stronger. It becomes magnetized when the current flows through it. It is used in the electromagnet as it loses its magnetism when the current stops flowing through it.

From the given options in the problem, Only the iron nail can be used as the metallic core of an electromagnet.

melomori [17]3 years ago
6 0
The nails would be used as they're made of iron:)
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Explanation:

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How does the chemical formula for water influence its chemical properties?
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The chemical formula is composed of hydrogen and oxygen where the two atoms are bonded through hydrogen bond type of bonding. In this pair, the oxygen is the more electronegative atom hence the electrons are more directed to it. Because of this, this creates electron polarity which affects the chemical property of water.

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You mix 200. mL of 0.400M HCl with 200. mL of 0.400M NaOH in a coffee cup calorimeter. The temperature of the solution goes from
GuDViN [60]

Answer : The enthalpy of neutralization is, 56.012 kJ/mole

Explanation :

First we have to calculate the moles of HCl and NaOH.

\text{Moles of HCl}=\text{Concentration of HCl}\times \text{Volume of solution}=0.400mole/L\times 0.200L=0.08mol

\text{Moles of NaOH}=\text{Concentration of NaOH}\times \text{Volume of solution}=0.400mole/L\times 0.200L=0.08mol

The balanced chemical reaction will be,

HCl+NaOH\rightarrow NaCl+H_2O

From the balanced reaction we conclude that,

As, 1 mole of HCl neutralizes by 1 mole of NaOH

So, 0.08 mole of HCl neutralizes by 0.08 mole of NaOH

Thus, the number of neutralized moles = 0.08 mole

Now we have to calculate the mass of water.

As we know that the density of water is 1 g/ml. So, the mass of water will be:

The volume of water = 200mL+200L=400mL

\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/ml\times 400mL=400g

Now we have to calculate the heat absorbed during the reaction.

q=m\times c\times (T_{final}-T_{initial})

where,

q = heat absorbed = ?

c = specific heat of water = 4.18J/g^oC

m = mass of water = 400 g

T_{final} = final temperature of water = 27.78^oC=273+25.10=300.78K

T_{initial} = initial temperature of metal = 25.10^oC=273+27.78=298.1K

Now put all the given values in the above formula, we get:

q=400g\times 4.18J/g^oC\times (300.78-298.1)K

q=4480.96J

Thus, the heat released during the neutralization = -4480.96 J

Now we have to calculate the enthalpy of neutralization.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy of neutralization = ?

q = heat released = -4480.96 J

n = number of moles used in neutralization = 0.08 mole

\Delta H=\frac{-4480.96J}{0.08mole}=-56012J/mole=-56.012kJ/mol

The negative sign indicate the heat released during the reaction.

Therefore, the enthalpy of neutralization is, 56.012 kJ/mole

8 0
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