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ad-work [718]
3 years ago
5

The smallest unit of an element

Chemistry
1 answer:
Sliva [168]3 years ago
8 0
The smallest unit of an element that retains the chemical and physical properties of an element is an Atom.
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How many moles of oxygen atoms are present in 5 moles of Mg3(PO4)2
Irina18 [472]

How many moles of oxygen atoms are present in 5 moles of Mg3(PO4)2

All you have to do is to create a ratio between the molecule and the oxygen atom.

5 moles of Mg3(PO4)2 (4x2 moles O/1 mole Mg3(PO4)2) = 40 moles of oxygen

5 0
3 years ago
The amount of energy that must be absorbed or lost to raise or lower the temperature of 1 g of liquid water by 1°C _____. See Co
Klio2033 [76]

Answer:

Specific heat capacity

Explanation:

Heat capacity is defined as amount of the heat supplied or absorbed by the given mass of the material so to make a unit change in the material's temperature.

The SI unit is Joule / kelvin (J/K).

It is an extensive property.  

While,  

<u>Specific heat capacity is the amount of heat absorbed or lost by one gram of mass of the substance to raise it's temperature by 1°C or 1 K </u>

<u>It is an intensive property. </u>

4 0
3 years ago
Question 10.
Katarina [22]
D should be the correct answer. Hope that helps.
3 0
3 years ago
Which is the best example of potential energy?
babymother [125]

Answer:

holding a basketball in the air

Explanation:

the ball has potential to have a certain amount of energy but hasn't exerted it yet.

8 0
3 years ago
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The following steps are unbalanced half-reactions involved in the nitrogen cycle. Balance each half-reaction to show the number
Vadim26 [7]

This is an oxidation reaction. The balanced equation is as follows:

      6H₂O  + N₂ → 2NO₃⁻+ 12H⁺  + 6e⁻

Rules to balance redox reaction in acidic medium

  1. Write the given equation in ionic form
  2. Identify elements undergoing oxidation ( charge increase, O.N inc) and reduction (charge dec, O.N dec)
  3. Break the equation into two halfs
  4. Balance the half equations

A. Balance all other atoms except Oxygen and hydrogen

B. Balance oxygen by adding H2O to the side deficient in oxygen

C. Balance hydrogen by adding H+ ions

D. Balance charge by adding electrons

5. Add the two half such that electrons gets cancelled

Oxidation number of N in N2 is 0 while in NO₃⁻, it is +5. Thus there is an increase in oxidation number, thus oxidation is taking place.

              N₂(g) → NO₃⁻(aq)

  • balance N.

           N₂ → 2NO₃⁻

  • balance O by adding H2O

          6H₂O  + N₂ → 2NO₃⁻

  • Now balance Hydrogen

            6H₂O  + N₂ → 2NO₃⁻+ 12H⁺

  • balance charge. 0 charge on left, -6 and + 12 on right. add 6e⁻ on right to balance.

             6H₂O  + N₂ → 2NO₃⁻+ 12H⁺  + 6e⁻

Thus we can conclude that since there is increase in oxidation number, oxidation is taking place.

learn more about balancing redox reactions at brainly.com/question/10203480

#SPJ4

3 0
1 year ago
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