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3 years ago

How to do balance chemical equiations

Chemistry

1 answer:

alex41 [277]3 years ago

4 0

Hey, lovely! It's a pretty lengthy process but here is a pretty clear video on how to do it. Hope this helps ya!

https://www.khanacademy.org/science/chemistry/chemical-reactions-stoichiome/balancing-chemical-equat...

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The temperature of a sample of water in the liquid phase is raised 30 degrees Celsius by the addition of 3762 J. What is the mas

Butoxors [25]

The answer is A because it’s how you calculate the mass

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3 years ago

He following balanced equation shows the formation of water. 2H2 + O2 mc020-1.jpg 2H2O How many moles of oxygen (O2) are require

mrs_skeptik [129]

Answer : The correct option is, 13.7 mole

Solution : Given,

Moles of $H_2$ = 27.4 moles

The given balanced chemical reaction is,

$2H_2+O_2\rightarrow 2H_2O$

From the balanced chemical reaction, we conclude that

As, 2 moles of $H_2$ react with 1 moles of $O_2$

So, 27.4 moles of $H_2$ react with $\frac{27.4}{2}=13.7$ moles of $O_2$

Therefore, the number of moles of oxygen $O_2$ required are, 13.7 moles

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3 years ago

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How many protons and electrons are present in Au+?

balandron [24]

Answer:

Protons: 79

Electrons: 78

Explanation:

1. The number of protons is the atomic number (The atomic number for Au on the periodic table is 79)

2. Since the charge is +1 (positive) it means that there's one more proton than electrons. So, 79-1 = 78 electrons

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3 years ago

A sample compound contains 5.723g Ag, 0.852g S and 1.695g O. Determine its empirical formula.

Lubov Fominskaja [6]

Answer:

$Ag_2SO_4$

Explanation:

Formula for the calculation of no. of Mol is as follows:

$mol=\frac{mass\ (g)}{molecular\ mass}$

Molecular mass of Ag = 107.87 g/mol

Amount of Ag = 5.723 g

$mol\ of\ Ag=\frac{5.723\ g}{107.87\ g/mol} =0.05305\ mol$

Molecular mass of S = 32 g/mol

Amount of S = 0.852 g

$mol\ of\ S=\frac{0.852\ g}{32\ g/mol} =0.02657\ mol$

Molecular mass of O = 16 g/mol

Amount of O = 1.695 g

$mol\ of\ O=\frac{1.695\ g}{16\ g/mol} =0.10594\ mol$

In order to get integer value, divide mol by smallest no.

Therefore, divide by 0.02657

$Ag, \frac{0.05305}{0.02657} \approx 2$

$S, \frac{0.02657}{0.02657} \approx 1$

$O, \frac{0.10594}{0.02657} \approx 4$

Therefore, empirical formula of the compound = $Ag_2SO_4$

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3 years ago

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What is the volume of 425g of ice if the density is 0.92g/mL

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Density=mass/ volume so you solve for volume and get 461.96 mL

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