Answer:
30 °C
Explanation:
When you pour water from one glass to the other, the heat energy will flow from the hot water to the cold.
You have equal masses of water in each glass. The hot water should cool down as much as the cold water warms up.
The final temperature should be halfway between the starting temperatures in each glass.
(10 °C + 50°C)/2 = 60 °C/2 = 30°C
The temperature of the full glass of water should be 30 °C.
Answer:
Mass = 11.16 g
Explanation:
Given data:
Mass of hydrogen = 8 g
Mass of oxygen = 10 g
Mass of water produced = ?
Solution:
Chemical equation:
2H₂ + O₂ → 2H₂O
Number of moles of hydrogen:
Number of moles = mass / molar mass
Number of moles = 8 g/ 2 g/mol
Number of moles = 4 mol
Number of moles of oxygen:
Number of moles = mass / molar mass
Number of moles = 10 g/ 32 g/mol
Number of moles = 0.31 mol
now we will compare the moles of hydrogen and oxygen with water.
O₂ : H₂O
1 : 2
0.31 : 2/1×0.31 = 0.62
H₂ : H₂O
2 : 2
4 : 4
Number of moles of water formed by oxygen are less this it will act as limiting reactant.
Mass of water:
Mass = number of moles × molar mass
Mass = 0.62 mol × 18 g/mol
Mass = 11.16 g
There are 1952.31g of nickel can be converted to the carbonyl with 3.55 m³ of CO at 100.7 kPa.
Given data
The reaction can be written as:
Ni+4CO ⟶
V(CO)=3.55
T=50°C=323.5K
p=100700Pa
Now, use the formula:
pV=nR*T
Where, P is pressure, V is volume and T is temperature. n=p∗V / R∗T
n=100700∗3.55 / 8.314∗323.15
It is known that,
n(CO)=133.059mol
n(Ni)=n(CO)/4=33.26mol
Mass can be determined by the formula:
Mole = mass / molar mass
Now, put the value of given data in above formula:
m(Ni)=nAr=33.26mol/58.69g/mol
m(Ni)=1952.31g
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Dimension analysis is to be used to solve this problem. First convert 1L to milliliters. That is equivalent to 1000 ml. Then by dimension analysis, multiply the volume ( 1000ml) to the density of oil (0.92 g/ml) resulting to the answer: 920 grams.
<u>Answer:</u> The increase in temperature is 7.14°C
<u>Explanation:</u>
To calculate the change in temperature, we use the equation:

where,
q = heat absorbed = 14.5 kJ = 14500 J (Conversion factor: 1 kJ = 1000 J)
m = mass of water = 485 g g
c = specific heat capacity of water = 4.184 J/g.°C
= change in temperature = ?
Putting values in above equation, we get:

Hence, the increase in temperature is 7.14°C