Thermal energy always flows spontaneously from the body that is at a higher temperature to the body that has a lower temperature.
In this case, the thermal energy flows from the hot beverage that is at the temperature t1 to the ice cube at the temperature t2 until the two reach the same temperature t3.
Where:
t1> t2 <t3.
The ice cube would emit heat if the temperature of the liquid with which it comes in contact with the smaller than that of the ice.
Answer:
Explanation:
given wave = 8.5 x 10⁻³ cos ( 172 x - 2730t )
here wave no k = 172
angular frequency ω = 2730
velocity of wave on the string
a )
v = ω / k
= 2730 / 172
= 15.87 m/s
time taken to travel full length
= 1.2 / 15.87
= 75.6 x 10⁻³ s
b )
For velocity of wave on the wire the formula is
T is tension and m is mass per unit length of wire
m = .0121 / ( 9.8 x 1.2 )
= 1.03 x 10⁻³ kg / m
15.87 =
W = .259 N
c ) wavelength λ = 2π / k
= 2 x 3.14 / 172
= .0182 m
no of wave length
n = 1.2 / .0182
= 66 approx .
Answer:
-140
Explanation:
A gas loses 80joules of heat.
The gas also does 60 joules of work
Therefore the change in internal energy can be calculated as follows
= -80 + (-60)
= -80-60
= -140
Hence the change in internal energy is -140
Iodine, chloride, and bromide
Answer:
1)
2)
Explanation:
<u>Projectile Motion</u>
When an object is launched near the Earth's surface forming an angle with the horizontal plane, it describes a well-known path called a parabola. The only force acting (neglecting the effects of the wind) is the gravity, which acts on the vertical axis.
The heigh of an object can be computed as
Where is the initial height above the ground level, is the vertical component of the initial velocity and t is the time
The y-component of the speed is
1) We'll find the vertical component of the initial speed since we have not enough data to compute the magnitude of
The object will reach the maximum height when . It allows us to compute the time to reach that point
Solving for
Thus, the maximum heigh is
We know this value is 8 meters
Solving for
Replacing the known values
2) We know at t=1.505 sec the ball is above Julie's head, we can compute