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seropon [69]
3 years ago
14

How do you find the weight of an object on an incline in physics?​

Physics
1 answer:
Nezavi [6.7K]3 years ago
8 0

Refers to the attachment for the answer.

Let us assume that the object of mass m is kept on the Inclined plane.

Now, there will act one force called as Component of the Weight along the Incline which is given by the Relation,

mgsinθ,

where θ is the angle which the incline makes with the surface or Angle of the Incline.

Now, If there will be no friction and the object is moving along the incline

Force = mgsinθ

⇒ ma = mgsinθ

∴ a = gsinθ

This case is valid when the angle of the Incline is greater than the angle of repose, which means the object is moving with no cause or acing of the force.

But sometimes when the object does not move without the action of force, I mean that the angle of repose is greater than the angle of the incline, then we need to apply the force so that the object can move then,

Force applied = mgsinθ

∴ a = gsinθ

It will change the cases when friction is involved.

Now, For velocity, It can be found by using the equation of Motions. Time, Distance or initial velocity, etc must be given if the question will be asked related to the velocity. So by using them, you can find that.

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A 12.0 μF capacitor is charged to a potential of 50.0 V and then discharged through a 265 Ω resistor. A)How long does the capaci
larisa [96]

(a) The time for the capacitor to loose half its charge is 2.2 ms.

(b) The time for the capacitor to loose half its energy is 1.59 ms.

<h3>Time taken to loose half of its charge</h3>

q(t) = q₀e-^(t/RC)

q(t)/q₀ = e-^(t/RC)

0.5q₀/q₀ = e-^(t/RC)

0.5 = e-^(t/RC)

1/2 =  e-^(t/RC)

t/RC = ln(2)

t = RC x ln(2)

t = (12 x 10⁻⁶ x 265) x ln(2)

t = 2.2 x 10⁻³ s

t = 2.2 ms

<h3>Time taken to loose half of its stored energy</h3>

U(t) = Ue-^(t/RC)

U = ¹/₂Q²/C

(Ue-^(t/RC))²/2C = Q₀²/2Ce

e^(2t/RC) = e

2t/RC = 1

t = RC/2

t = (265 x 12 x 10⁻⁶)/2

t = 1.59 x 10⁻³ s

t = 1.59 ms

Thus, the time for the capacitor to loose half its charge is 2.2 ms and the time for the capacitor to loose half its energy is 1.59 ms.

Learn more about energy stored in capacitor here: brainly.com/question/14811408

#SPJ1

6 0
2 years ago
An athlete of mass 70kg runs at a velocity of 6ms5-1 calculate the kinetic energy of the athlete.​
Molodets [167]
KE=1/2 mv²
= 1/2 × 70 × (6)²
= 1260
8 0
3 years ago
Warning triangles, flares, a vehicle's hazard lights, or emergency vehicles ahead, are all clues that you might be approaching _
daser333 [38]

Answer:

B. A collision scene

Explanation:

It could have been a parade ceremony, but, if you notice the vehicle's hazard lights or an emergency vehicle ahead, it is common sense to figure that they is a collision scene nearby.

8 0
3 years ago
Please i need your help w/h/w you make the following measurements if an object:42kg, and 22m​
Rufina [12.5K]

Answer:

1.9 kg/m^3

Explanation:

The density of an object is given by

d=\frac{m}{V}

where

m is the mass of the object

V is its volume

In this problem,

m = 42 kg

V = 22 m^3

Substituting into the equation, we find the object's density:

d=\frac{42 kg}{22 m^3}=1.9 kg/m^3

8 0
3 years ago
A mango is dropped and fall freely from rest. What are its position and velocity after 1.0secs,2.0secs,and 3.0secs
irakobra [83]

Answer:

sxsdfsd

Explanation:

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