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2 years ago

How do you find the weight of an object on an incline in physics?

Physics

1 answer:

Nezavi [6.7K]2 years ago

8 0

Refers to the attachment for the answer.

Let us assume that the object of mass m is kept on the Inclined plane.

Now, there will act one force called as Component of the Weight along the Incline which is given by the Relation,

mgsinθ,

where θ is the angle which the incline makes with the surface or Angle of the Incline.

Now, If there will be no friction and the object is moving along the incline

Force = mgsinθ

⇒ ma = mgsinθ

∴ a = gsinθ

This case is valid when the angle of the Incline is greater than the angle of repose, which means the object is moving with no cause or acing of the force.

But sometimes when the object does not move without the action of force, I mean that the angle of repose is greater than the angle of the incline, then we need to apply the force so that the object can move then,

Force applied = mgsinθ

∴ a = gsinθ

It will change the cases when friction is involved.

Now, For velocity, It can be found by using the equation of Motions. Time, Distance or initial velocity, etc must be given if the question will be asked related to the velocity. So by using them, you can find that.

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Answer:

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Solution:

As per the question:

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Thickness of the tennis ball, t = 2.0 mm = $2.0\times 10^{- 3}\ m$

Max velocity of the tennis ball, $v_{m} = 200\ mph$ = 89 m/s

Now,

The maximum kinetic energy of the tennis ball is given by:

$KE = \frac{1}{2}mv_{m}^{2} = \frac{1}{2}\times 0.1\times 89^{2} = 396.05\ J$

Kinetic energy of the tennis ball, KE' = $\frac{1}{2}mv^{2} = 0.5\times 0.1\times 54^{2} = 154.8\ m/s$

Now, the distance the ball can penetrate to is given by:

$\eta = \frac{\bar{h}}{\sqrt{2m(KE - KE')}}$

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$\eta = \frac{1.0545\times 10^{- 34}}{\sqrt{2\times 0.1(396.05 - 154.8)}}$

$\eta = 1.52\times 10^{-35}\ m$

Now,

We can calculate the tunneling probability as:

$P(t) = e^{\frac{- 2t}{\eta}}$

$P(t) = e^{\frac{- 2\times 2.0\times 10^{- 3}}{1.52\times 10^{-35}}} = e^{-2.63\times 10^{32}}$

$P(t) = e^{-2.63\times 10^{32}}$

Taking log on both the sides:

$logP(t) = -2.63\times 10^{32} loge$

$P(t) = 10^{- 1.17\times 10^{32}}$

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<h3>What is the scientific method?</h3>

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Since the student in question just put forward an opinion without testing it out using the scientific method, the statement is not a scientific claim.

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How do you find the weight of an object on an incline in physics?​

How do you find the weight of an object on an incline in physics?