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anygoal [31]
3 years ago
12

An atom bonds with another atom. What is the best classification for this reaction?

Chemistry
2 answers:
defon3 years ago
5 0
Chemical would be the correct answer
kiruha [24]3 years ago
3 0

The best classification of reaction in which  an  atom bonds with another atom   is <u>chemical reaction</u>

<em><u> </u></em><u><em>Explanation</em></u>


In a chemical reaction, reactants come into contact to  each other.

Bond   between  atoms in the reactant  are broken down and then rearrange to form new  bonds  which form product


For   example of a chemical reaction is as below

N2 + 3H2 → 2NH3

N2 and H2  are atoms that come in to contact to each  other to form NH3.

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How much energy must a 10 gram block of ice gain in order to melt ?
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2 years ago
Which of these alkalis has the most stable fluoride?
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The correct option is B. The alkali metals combine directly with halogens forming high melting point crystalline solids that have high negative enthalpies of formation. The entalphy of formation for lithium bromide is the highest and the values decrease down the group, thus, lithium is the most stable while cesium is the least stable. 
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3 years ago
The​ half-life of​ plutonium-241 is approximately 13 years. a. How much of a sample weighing 2 g will remain after 70 ​years? b.
Studentka2010 [4]

Answer: A) 0.0480 grams and B) 56.16 years.

Explanation: Half live is the time in which the amount of radioactive substance remains halve of its initial amount.

The formula we use for solving this type of problem is:

\frac{N}{N_0}=(\frac{1}{2})^n

where, N_0 is the initial amount and N is the remaining amount of radioactive substance and n is the number of half lives.

n=T/t_1_/_2

where, T is the time and t_1_/_2 is half life.

A) from given data, N_0 = 2 g

T = 70 years

t_1_/_2 = 13 years

N= ?

n=\frac{70years}{13years}

n = 5.38

\frac{N}{2g}=(\frac{1}{2})^5^.^3^8

\frac{N}{2g}=0.0240

N = 0.0480 g

So, 0.0480 grams of the substance will be remaining after 70 years.

B) N_0 = 2 g

N = 0.1 g

T = ?

Let's first calculate the value of n for this.

\frac{0.1}{2}=(\frac{1}{2})^n

0.05=0.5^n

Taking log to both sides:

log0.05=nlog0.5

-1.301=n(-0.3010)

n=\frac{1.3010}{0.3010}

n = 4.32

Half life is 13 years, so we can calculate the time as:

n=T/t_1_/_2

T=n*t_1_/_2

T=4.32*13years

T = 56.16 years

So, it will take 56.16 years for the radioactive substance to decay from 2 g to 0.1 g.

8 0
4 years ago
Read 2 more answers
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