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creativ13 [48]
3 years ago
8

What weather does spikes or icicles bring?

Chemistry
1 answer:
Snowcat [4.5K]3 years ago
4 0
When it drops below 0 / freezing
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Help!!!!!! i have not done science since December!!!!!!! _________ is the distance traveled during a specific unit of time.
Natalka [10]

Answer:

Velocity is the distance traveled during a specific unit of time

3 0
3 years ago
Determine the oxidation number of sodium in Na202
Olegator [25]

Answer:

+1

Explanation:

Na₂O₂

NOTE: the oxidation number of oxygen is always –2 except in peroxides where it is –1.

Thus, we can obtain the oxidation number of sodium (Na) in Na₂O₂ as illustrated below:

Na₂O₂ = 0 (oxidation number of ground state compound is zero)

2Na + 2O = 0

O = –1

2Na + 2(–1) = 0

2Na – 2 = 0

Collect like terms

2Na = 0 + 2

2Na = 2

Divide both side by 2

Na = 2/2

Na = +1

Thus, the oxidation number of sodium (Na) in Na₂O₂ is +1

5 0
3 years ago
If 1. 3618 moles of AsF3 are allowed to react with 1. 0000 mole of C2Cl6, what would be the theoretical yield of AsCl3, in moles
VARVARA [1.3K]

Answer:

AsF3:C2CI6

4:3

1.3618 moles: 1.02135 moles(1.3618÷4×3)

C2CI6 is the limting reagent

So the number of moles for AsCI3 is 0.817 moles( number of moles of the limting reagant) ÷3 ×4 (according to ratio by balancing chemical equation)=1.09 moles(3 s.f.)

or

Balanced equation

4AsF3 + 3C2Cl6 → 4AsCl3 + 3C2Cl2F4

Use stoichiometry to calculate the moles of AsCl3 that can be produced by each reactant.

Multiply the moles of each reactant by the mole ratio between it and AsCl3 in the balanced equation, so that the moles of the reactant cancel, leaving moles of AsCl3.

Explanation:

5 0
3 years ago
What are the uses of crude oil?
vampirchik [111]

Answer:

they are use to make  tar, asphalt, paraffin wax, and lubricating oils.

Explanation:

7 0
3 years ago
AV<br> 5. How many grams are in 0.52 moles of H3PO4?
Hoochie [10]

Answer:

50.96g

Explanation:

Given parameters:

Number of moles of H₃PO₄   = 0.52moles

Unknown:

Mass of the compound  = ?

Solution:

To find the mass of the compound:

    Mass  = number of moles x molar mass of H₃PO₄

Molar mass of H₃PO₄ = 3(1) + 31 + 4(16)  = 98g/mol

  Mass  = 0.52 x 98  = 50.96g

3 0
3 years ago
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