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3 years ago

8.

Chemistry

1 answer:

mrs_skeptik [129]3 years ago

7 0

Mass of Oxygen : 47.9

<h3>Further explanation</h3>

Given

2S03 (g)⇒ 2S02 (g) + O2 (g)

240 g SO3

Required

mass of Oxygen

Solution

mol SO3 :

= 240 g : 80.1 g/mol

= 2.996

From the equation, mol O2 :

= 1/2 x mol SO3

= 1/2 x 2.996

= 1.498

mass O2 :

= 1.498 mol x 32 g/mol

= 47.9

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6. Cuando se oxidan en el aire 12,120 g de vapor de Zinc se obtienen 15,084 g del óxido. ¿Cuál es la fórmula empírica del óxido?

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Answer:

12120 g + O2 = 15084 g

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m óxido = 15.084 Kg

1. calcular la masa de cinc en gramos

g = 12,120 Kg x 1000 = 12120 g de cinc

g = 15.084 Kg x 100 = 15084 g de oxígeno

2. calcular gramos de Oxigeno

g O = 15084 g - 12120 g = 2964 g O2

3. calcular % de Zn y O

%m/m ( m soluto / m solc.) x 100

%m/m (Zn) = ( 1210 g / 15084 g ) x 100

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% m/m (Zn) = 19.65 % = 19.65 g

4. Calcular moles de cada elemento

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O: 19.65 g / 16 g/mol = 1.228 mol

5. dividir entre el menor de los elementos

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O: 1.228 mol / 1.228 mol = 1

6. Fórmula empírica: ZnO

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