"Nitrogen gas" makes up 75% (approx. 78%) of the earth's atmosphere
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Answer:
11.106 Mev.
Explanation:
Sr⁸⁸ → Sr ⁸⁷ + ₀n¹
87.905612 86.908877 1.008664 ( atomic masses in amu )
mass defect = ( 86.908877 + 1.008664) - 87.905612 = .011929 amu.
Equivalent energy in MeV = .011929 x 931 = 11.106 MeV
Answer:
The equipment to use is: a beaker, a fixed amount of water, a thermometer.
The mass of water, the time, the temperature for each time should be noted and a graph of Temperature versus time should be made
Explanation:
The design of an experiment is to place the beaker in the microwave, with a good amount of water (approximately ⅔ of its capacity) and turn it on for small periods of time, generally the minimum is 30 s, quickly open the microwave, place a thermometer or better yet an infrared thermometer to measure the temperature of the water; repeat this several times.
The advantage of the infrared thermometer is that it reduces the transfer of heat between the water and the thermometer.
The mass of water, the time, the temperature for each time should be noted and a graph of Temperature versus time should be made.
The equipment to use is: a beaker, a fixed amount of water, a thermometer.
The main precaution that must be taken is not to open the microwave while it is on.
Answer:
The transmitted intensity through all polarizers = 34.73
Explanation:
Given :
Incident intensity = 
Angle between the transmission axis and polarizer optic axis = 18°
According to the malus law, when unpolarized or polarized light passes through polarizing disk, the intensity of the transmitted light is directly proportional to the square of the cosine of angle between the transmission axis and polarizer optic axis.
∴ 
Where 
transmitted intensity, 
incident intensity, 
angle between the transmission axis and polarizer optic axis.
Here, there are four polarizing disks so that.
from first disk,
∴ 
₁ 
18°
= 
×
= 
Now ₁ behave as an incident light for second polarizer so we only multiply
term
so we write,
∴ ₂ = ×
From third polarizer,
∴ ₃ = 
×
From forth polarizer,
∴ ₄ = 
×
Therefor, the the transmitted intensity through forth polarizer = 34.73 
.
True.<span>
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