Question

A pen rolls off a 0.55–meter high table with an initial horizontal velocity of 1.2 meters/second. At what horizontal distance from the base of the table will the pen land?

Answer 1

We are asked in the problem to determine the horizontal distance achieved by rolling of a pen from a vertical distance of 0.55 m at 1.2 m/s.
we use the formula in this case,

t = √[2y/g] 
where g is the gravitational acceleration
t = √[2*0.55/9.8] =0.335 s

X = v * t = 1.2 m/s *0.335 s = 0.4 m

Answer 2

To calculate the horizontal distance traveled by the ball, we first calculate the total time it takes to reach the ground as follows:


t = √[2y/g] = √[2(0.55) / 9.81]
t = 0.33 s

The horizontal distance would be

X = Vx*t = 1.2*√[2*.55/9.8] = 0.4 m

Hope this helps.