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worty [1.4K]
3 years ago
6

Putting a beaker of water in a microwave and turning it on for a minute or two will increase the temperature of the water. Descr

ibe an experiment to investigate the relationship between the time the microwave is on and the increase in temperature of water in a beaker. In your answer, include: The equipment you will use The measurements you will take The safety precautions you will take
Physics
1 answer:
Jobisdone [24]3 years ago
4 0

Answer:

The equipment to use is: a beaker, a fixed amount of water, a thermometer.

The mass of water, the time, the temperature for each time should be noted and a graph of Temperature versus time should be made

Explanation:

The design of an experiment is to place the beaker in the microwave, with a good amount of water (approximately ⅔ of its capacity) and turn it on for small periods of time, generally the minimum is 30 s, quickly open the microwave, place a thermometer or better yet an infrared thermometer to measure the temperature of the water; repeat this several times.

The advantage of the infrared thermometer is that it reduces the transfer of heat between the water and the thermometer.

The mass of water, the time, the temperature for each time should be noted and a graph of Temperature versus time should be made.

The equipment to use is: a beaker, a fixed amount of water, a thermometer.

The main precaution that must be taken is not to open the microwave while it is on.

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Water flows into a swimming pool at the rate of 5.85 gal/min. If the pool dimensions are 21.2 ft wide, 46.1 ft long and 19.4 ft
Lana71 [14]

First, calculate volume:

volume = 21.2 ft * 46.1 ft * 19.4 ft

volume = 18,960 ft^3

 

Convert to gallon:

volume = 18,960 ft^3 * (12 in / 1 ft)^3 * (1 gallon / 231 in^3)

volume = 141,830.71 gallon

 

Therefore the time is:

time = 141,830.71 gallon / (5.85 gal/min)

time = 24,244.57 min

6 0
3 years ago
Spiderman has a mass of 80 kg. He knows his webbing will break if it is exposed to a 200 N force. What is the maximum height he
likoan [24]

Answer:

This depends on the writers

if they want they can make spiderman deny the laws of nature

8 0
3 years ago
A red car and a green car, identical except for the color, move toward each other in adjacent lanes and parallel to an x axis.At
timurjin [86]

Answer:

a) The initial velocity of the green car is -13 m/s

b) The acceleration of the green car is - 2.25 m/s²

Explanation:

The equation for the position of objects moving in a straight line with constant acceleration is as follows:

x = x0 + v0·t + 1/2·a·t²

where:

x = position

x0 = initial position

v0 = initial velocity

a = acceleration

t = time

If the velocity is constant, then a = 0 and x = x0 + v·t

a)The initial position of the red and green car is 0 m and 220 m respectively. We know that at 44.5 m the cars pass each other if the red car has a constant velocity of 20 km/h. So let´s find how much time it takes the cars to pass each other in this case:

The position of the red car is:

x = x0 + v·t

then:

0.0445 km = 0 km + 20 km/h · t

t = 0.0445 km/ 20 km/h = 8.0 s

We also know that if the red car has a velocity of 40 km/h, both cars pass each other at 76.6 m. So let´s find the time it takes the cars to reach that position using the equation for the red car:

0.0766 km = 0 km + 40 km/h · t

t = 0.0766 km / 40 km/h = 6.9 s

The position of the green car at t= 6.9 s and t = 8.0 s must be the same as the red car because both cars pass each other at those times.

Then, for the green car:

x = x0 + v0·t + 1/2·a·t²

0.0445 km = 0.220 km + v0 · 8.0 s + 1/2·a· (8.0 s)²

and

0.0766 km = 0.220 km + v0 · 6.9 s + 1/2·a· (6.9 s)²

Now we have a system of two equations with two unknowns.

Solving for "a" in the first equation

0.0445 km - 0.220 km - v0 · 8.0 s = 32 s²·a

(-0.176 km - v0 · 8.0 s) / 32 s² = a

Replacing a = (-0.176 km - v0 · 8.0 s) / 32 s² in the second equation and solving for v0:

0.0766 km = 0.220 km + v0 · 6.9 s + 1/2·((-0.176 km - v0 · 8.0 s)/32 s²)·(6.9 s)²

-0.143 km = v0 · 6.9 s - 0.74(0.176 km + v0 · 8.0 s)

-0.143 km = v0 · 6.9 s - 0.130 km - v0 · 5.9 s

-0.143 km + 0.130 km = v0 · 6.9 s - v0 · 5.9 s

-0.013 km = 1 s · v0

v0 = -13 m/s

b) The acceleration of the green car is:

a = (-0.176 km - v0 · 8.0 s) / 32 s²

a = (-0.176 km - (-0.013 km/s) · 8.0 s) / 32 s² = -2.25 m/s²

3 0
3 years ago
This physics problem is kinda complicated to my small brains...
Veronika [31]

Answer:

\huge\boxed{\sf P.E. = 14700\ Joules}

Explanation:

This work done is in the form of Potential Energy so we'll use the formula of Potential Energy.

<u>Given Data:</u>

Mass = m = 250 kg

Acceleration due to gravity = g = 9.8 m/s²

Height = h = 6 m

<u>Required:</u>

Work Done in the form of Potential Energy = P.E. = ?

<u>Formula:</u>

P.E. = mgh

<u>Solution:</u>

P.E. = (250)(9.8)(6)

P.E. = 14700 Joules

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
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3 years ago
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Liono4ka [1.6K]
<h2>your answer is going to be image 1 that one looks the most decent </h2>
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3 years ago
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