The distance travelled by the body on last second of its upwards journey is 4.935m
What is projectile motion?
A projectile is an object or particle that is launched toward the surface of the Earth and moves along a curved path only under the influence of gravity.
To solve this question, consider the horizontal distance to be H and 
 distance traveled by the body in the last second be d
 

H=510.2m
Now time taken to reach a height of 
510.2 m= ![\sqrt[n]{2H/g}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7B2H%2Fg%7D)
=10.2 seconds
Now,



d=4936m
So, the correct answer is '4.936m'.
To know more about projectile motion visit:
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In this case, volume of the can remains constant. The relationship between pressure and temperature at constant volume is given by:
P/T = Constant
Then

Where
P1 = 40 psi
P2 = ?
T1 = 60°F ≈ 289 K
T2 = 90°F ≈ 305 K (note, 363 K is not right)
Substituting;
 
 
        
        
        
Answer:
a. 572Btu/s
b.0.1483Btu/s.R
Explanation:
a.Assume a steady state operation, KE and PE are both neglected and fluids properties are constant.
From table A-3E, the specific heat of water is  , and the steam properties as, A-4E:
, and the steam properties as, A-4E:
 
Using the energy balance for the system:

Hence, the rate of heat transfer in the heat exchanger is 572Btu/s
b. Heat gained by the water is equal to the heat lost by the condensing steam. 
-The rate of steam condensation is expressed as:

Entropy generation in the heat exchanger could be defined using the entropy balance on the system:

Hence,the rate of entropy generation in the heat exchanger. is 0.1483Btu/s.R
 
        
             
        
        
        
<span>B. because they cannot make light rays converge</span>