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dexar [7]
3 years ago
9

What is the distance from the peak of one wave to the peak of the next wave called?

Biology
2 answers:
lions [1.4K]3 years ago
7 0

Answer:

Explanation:

wavelength| The distance between one peak or crest of a wave of light, heat, or other energy and the next corresponding peak or crest. amplitude| The height of a crest (or the depth of a trough) of a wave.

UNO [17]3 years ago
5 0

Answer:

Wavelength refers to the length of a wave from one peak to the next. The amplitude or height of a wave is measured from the peak to the trough.

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What can neither be created nor destroyed by ordinary means?
MAVERICK [17]
Energy can be converted from one form to another, but it cannot be created or destroyed in ordinary chemical or physical means. It states that matter can be neither created nor destroyed in ordinary chemical or physical changes.
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4 years ago
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Cystic fibrosis is most common in individuals of Northern European descent, affecting 1 in 3200 newborns. Assuming that these al
IgorLugansk [536]

Answer:

0.0177

Explanation:

Cystic fibrosis is an autosomal recessive disease, thereby an individual must have both copies of the CFTR mutant alleles to have this disease. The Hardy-Weinberg equilibrium states that p² + 2pq + q² = 1, where p² represents the frequency of the homo-zygous dominant genotype (normal phenotype), q² represents the frequency of the homo-zygous recessive genotype (cystic fibrosis phenotype), and 2pq represents the frequency of the heterozygous genotype (individuals that carry one copy of the CFTR mutant allele). Moreover, under Hardy-Weinberg equilibrium, the sum of the dominant 'p' allele frequency and the recessive 'q' allele frequency is equal to 1. In this case, we can observe that the frequency of the homo-zygous recessive condition for cystic fibrosis (q²) is 1/3200. In consequence, the frequency of the recessive allele for cystic fibrosis can be calculated as follows:

1/3200 = q² (have two CFTR mutant alleles) >>  

q = √ (1/3200) = 1/56.57 >>

- Frequency of the CFTR allele q = 1/56.57 = 0.0177  

- Frequency of the dominant 'normal' allele p = 1 - q = 1 - 0.0177 = 0.9823

4 0
3 years ago
HELP ASAP JUST ANSWER I GIVE BRAINLYYYYY<br><br> ily &lt;3
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1.) Cladogram
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5 0
4 years ago
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Answer:

Option (a) and (d).

Explanation:

The breaks in DNA molecule may occur due to replication error and oxidizing agent. The double-stranded breaks in DNA can be corrected by Homologous end joining and non homologous end joining.

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Thus, the correct answer is option (a) and (d).

3 0
4 years ago
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