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sertanlavr [38]
3 years ago
5

1 divided by 1/5????????

Mathematics
2 answers:
Neko [114]3 years ago
8 0

Answer:

the answer is 5

Step-by-step explanation:

Solnce55 [7]3 years ago
8 0

Answer:

5

Step-by-step explanation:

To find this answer, we are basically multiplying 1 by 5. Therefore, the answer is 5.

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(2-7m^6)^2<br><br><br> i dont know this
Pavel [41]
(2-7m^6)^2

rearrange terms:

(2-7m^6)^2

(-7m^6 + 2)^2

expand the squares:

(-7m^6 + 2)^2

(-7m^6 + 2)(-7m^6 + 2)

distribute:

(-7m^6 + 2)(-7m^6 + 2)

-7(-7m^6 + 2) • m^6 + 2(-7m^6 + 2)

distribute:

-7(-7m^6 + 2) • m^6 + 2(-7m^6 + 2)

49m^12 - 14m^6 + 2(-7^6 +2)

distribute:

49m^12 - 14m^6 + 2(-7^6 +2)

49m^12 - 14m^6 - 14m^6 + 4

combine like terms:

49m^12 - 14m^6 - 14m^6 + 4

49m^12 - 28m^6 + 4

solution:

49m^12 - 28m^6 + 4



please mark brainliest and hope it helps
7 0
3 years ago
the length of a rectangle is 6 meters less than twice the width. The area of the rectangle is 140m². Find the dimensions of the
AveGali [126]

Answer:

Here's what we know:

A = Lw (Area is length times width)

L = 2w + 6 (length is twice the width plus 6)

A = 140 (Area is 140 m2)

Plug in the variable values:

140 = w(2w + 6)

Distribute:

140 = 2w2 + 6w

Subtract 140:

2w2 + 6w - 140 = 0

Factor out a 2:

2(w2 + 3w - 70) = 0

Divide both sides by 2:

w2 + 3w - 70 = 0

(w + m)(w - n)

When we factor out the quadratic, we know it's going to be a +/- situation because the c value in the quadratic is negative, and the two numbers are going to be three away, the plus next to the 3 meaning that the larger number is going to be positive:

(w + 10)(w - 7) = 0

w = -10, 7

We can't have a negative length, so we can toss out the -10, leaving us with w = 7 meters.

L = 2 * 7 + 6

L = 14 + 6

L = 20

Check:

140 = 20 * 7

140 = 140

8 0
2 years ago
Read 2 more answers
Answer pls! No spam!
gulaghasi [49]

Answer:

Check the attachment.

3 0
2 years ago
Mya creates the
liubo4ka [24]
Mya should put 3/5 in each serving.
5 0
3 years ago
Can't figure it out!!
Zanzabum
\bf slope = {{ m}}= \cfrac{rise}{run} \implies &#10;\cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby &#10;\begin{array}{llll}&#10;average\ rate\\&#10;of\ change&#10;\end{array}\\\\&#10;-------------------------------\\\\&#10;f(x)= \cfrac{1}{x}  \qquad &#10;\begin{cases}&#10;x_1=2\\&#10;x_2=b&#10;\end{cases}\implies \cfrac{f(b)-f(2)}{b-2}=-\cfrac{1}{10}&#10;\\\\\\&#10;\cfrac{\frac{1}{b}-\frac{1}{2}}{b-2}=-\cfrac{1}{10}\implies &#10;\cfrac{\frac{2-b}{2b}}{b-2}=-\cfrac{1}{10}\implies \cfrac{2-b}{2b}=-\cfrac{b-2}{10}&#10;\\\\\\&#10;

\bf \cfrac{2-b}{2b}=\cfrac{2-b}{10}\implies 20-10b=4b-2b^2\impliedby cross-multiplying&#10;\\\\\\&#10;2b^2-4b-10b+20=0\implies 2b^2-14b+20=0&#10;\\\\\\&#10;b^2-7b+10=0\implies &#10;(b-2)(b-5)=0\implies b=&#10;\begin{cases}&#10;\boxed{5}\\&#10;2&#10;\end{cases}
8 0
3 years ago
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