Answer:
F = 118 N
Explanation:
Assume Ann and Bob lift at their respective ends of the table
Sum moments about Bob's position to zero.
Let F be Ann's upward force
F[2.25] - 18.5(9.80)[2.25 / 2] - 8.33(9.80)[0.750] = 0
F = 117.86133333...
Answer:
zero
Explanation:
q = 6.4 nC = 6.4 x 1 0^-9 C
d = 16 cm = 0.16 m
r = 16 / 2 = 8 cm = 0.08 m
Electric field at P due to the charge placed at A
Ea = k q / r^2
Ea = ( 9 x 10^9 x 6.4 x 10^-9) / (0.08 x 0.08) Towards right
Ea = 9000 Towards right
Electric field at P due to the charge placed at B
Eb = k q / r^2
Eb = ( 9 x 10^9 x 6.4 x 10^-9) / (0.08 x 0.08) Towards left
Eb = 9000 Towards left
The magnitude of electric field is same but teh direction is opposite, so the resultant electric field at P is zero.
The kelvin temperature/scale i think
Answer:
32 turns
Explanation:
From the expression for the induced emf,
E = (N)(B)(A) w
E = emf = 24 V
N = number of turns = ?
B = magnetic field strength = 0.10 T
A = Cross sectional Area of the loop = 100 cm² = 0.01 m²
w = Angular speed = (2πf) = (2π × 120) = 754.3 rad/s
24 = N (0.1)(0.01)(754.3)
N = (24/0.7543)
N = 31.8 ≈ 32 turns.
Hope this Helps!!!