Molecular formulas:
- CH₂O;
- C₂H₄O₂;
- C₆H₁₂O₆.
<h3>Explanation</h3>
The empirical formula of a compound tells only the ratio between atoms of each element. The empirical formula CH₂O indicates that in this compound,
- for each C atom, there are
- two H atoms, and
- one O atom.
The molecular weight (molar mass) of the molecule depends on how many such sets of atoms in each molecule. The empirical formula doesn't tell anything about that number.
It's possible to <em>add</em> more of those sets of atoms to a molecular formula to increase its molar mass. For every extra set of those atoms added, the molar mass increase by the mass of that set of atoms. The mass of one mole of C atoms, two mole of H atoms, and one mole of O atoms is 
.
- CH₂O- 30.0 g/mol;
- C₂H₄O₂- 30.0 + 30.0 = 2 × 30.0 = 60.0 g/mol;
- C₃H₆O₃- 30.0 + 30.0 + 30.0 = 3 × 30.0 = 90.0 g/mol.
It takes one set of those atoms to achieve a molar mass of 30.0 g/mol. Hence the molecular formula CH₂O.
It takes two sets of those atoms to achieve a molar mass of 60.0 g/mol. Hence the molecular formula C₂H₄O₂.
It takes 
sets of those atoms to achieve a molar mass of 180.0 g/mol. Hence the molecular formula C₆H₁₂O₆.
The ball's horizontal and vertical velocities at time 
are
but the ball is thrown horizontally, so 
. Its horizontal and vertical positions at time are
The ball travels 22 m horizontally from where it was thrown, so
from which we find the time it takes for the ball to land on the ground is
When it lands, 
and
The final momentum of the system would be 6680 Kg m/s
<h3>What is momentum?</h3>
It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle, and the momentum of any particle is expressed in Kg m/s unit.
Mathematically the formula of the momentum is
P = mv
Two cars are driving toward each other in a straight line. Car A is 1400 kg and driving at 11 m/s. Car B is 1090 kg and driving at 8 m/s. If the two cars collide inelastically, As we know that the momentum of a system is conserved during the collision
initial momentum = final momentum
the initial momentum of the system = 1400 ×11 + 1090×(-8)
= 6680 Kg m/s
The final momentum of the system = 6680 Kg m/s
Thus,The final momentum of the system would be 6680 Kg m/s
Learn more about momentum from here
brainly.com/question/17662202
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Answer: The second option.When
the current flows up the wire, the magnetic field flows out on the left
side of the wire and in on the right side of the wire.Explanation:
The first figure that I copy here with is the figure corresponding to this question.
The thumb is pointing upward.
The rule is that the thumb aims to the direction of the flow of current and the other fingers give the field lines.
The second figure that I attach is a free image from internet and it shows the direction of both the current and the fiedl lines.
So, the conclusion is that
the current goes upward the wire and the field lines go out of the paper (screen) for the points to the left of the wire and in on the right side of the wire.
As we can see in the figure attached here
The velocity of aircraft is given as
at 225 degree
velocity of wind is given as
at 315 degree
so here the net velocity of aircraft will be the vector sum of aircraft speed and wind speed
since in the figure we can see that the two speeds are perpendicular to each other
so we can say that the resultant of two speed can be given by using Pythagoras theorem
so we will have
so net speed of aircraft will be 154 km/h
