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Murljashka [212]
3 years ago
14

If you throw a raw egg against a wall, you'll break it, but if you throw it with the same speed into a sagging sheet it won't br

eak. why? 1. the sheet is much slicker than the wall. 2. the breaking egg causes a larger impact time, decreasing the force. 3. the impact time when the egg strikes a sagging sheet is long, so the impact force is small. 4. the velocity of the egg decreases faster in the sheet than on the wall.
Physics
1 answer:
SashulF [63]3 years ago
4 0
<span>The egg doesn't break when it hits the sheet because the impact time is longer. Momentum means the egg is slowed rather than coming to an abrubt halt. The softer the object that the egg hits, the longer the time it takes to break. A sheet is so soft that the force is never high enough for the egg to break.</span>
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A 4 cm diameter "bobber" with a mass of 3 grams floats on a pond. A thin, light fishing line is tied to the bottom of the bobber
Tasya [4]

Answer:

Explanation:

Calculate the volume of the lead

V=\frac{m}{d}\\\\=\frac{10g}{11.3g'cm^3}

Now calculate the bouyant force acting on the lead

F_L = Vpg

F_L=(\frac{10g}{11.3g/cm^3} )(1g/cm^3)(9.8m/s^2)\\\\=8.673\times 10^{-3}N

This force will act in upward direction

Gravitational force on the lead due to its mass  will act in downward direction

Hence the difference of this two force

T=mg-F_L\\\\=(10\times10^{-3}kg(9.8m/s^2)-8.673\times 10^{-3}\\\\=8.933\times10^{-3}N

If V is the volume submerged in the water then bouyant force on the bobber is

F_B=V'pg

Equate bouyant force with the tension and gravitational force

F_B=T_mg\\\\V'pg=\frac{(8.933\times10^{-2}N)+mg}{pg} \\\\V'=\frac{(8.933\times10^{-2}N)+mg}{pg}

Now Total volume of bobble is

\frac{V'}{V^B} =\frac{\frac{(8.933\times10^{-2})+Mg}{pg} }{\frac{4}{3} \pi R^3 }\times100\\\\=\frac{\frac{(8.933\times10^{-2})+(3)(9.8)}{(1000)(9.8)} }{\frac{4}{3} \pi (4.0\times10^{-2})^3 }\times100\\\\

=\large\boxed{4.52 \%}

7 0
3 years ago
all objects near the earths surface-regardless of size and weight have the same force of gravity acting on them. is it true or f
pickupchik [31]

False: the force of gravity acting on different objects is different and depends on their mass

Explanation:

The answer is false.

The force of gravity acting on an object (also known as weight) near the Earth's surface is given by:

F=mg

where:

m is the mass of the object

g=9.8 m/s^2 is the acceleration of gravity

We see from the formula that the force of gravity acting on an object depends on the mass: the larger the mass of the object, the stronger the gravitational force acting on it, and the smaller the mass, the weaker the force of gravity.

The factor that does not change is the acceleration of gravity, which is constant (9.8 m/s^2) if we are near the Earth's surface, and implies that all the objects in free fall accelerate at the same rate towards the ground, regardless of their size and weight.

Learn more about forces and weight here:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

5 0
3 years ago
Awave has a period of 1. What is its frequency?
Andrei [34K]

Answer:

Frequency, f = 1 unit

Explanation:

It is given that,

Period of the wave, T = 1 unit

We need to find the frequency of the wave. There exist an inverse relationship between period and the frequency of the wave. It is given by :

T=\dfrac{1}{f}

Or

f=\dfrac{1}{T}

f=\dfrac{1}{1\ units}

f = 1 unit

So, the frequency of the wave is 1 unit. Hence, this is the required solution.

4 0
4 years ago
I need help with the question 8B
ratelena [41]
The answer of this is C
3 0
3 years ago
15. Calculate The coefficient of kinetic friction be-
allochka39001 [22]

Answer:

Wt = 26.84 [N]

Explanation:

In order to solve this problem we must use the definition of work in physics. Which tells us that this is equal to the product of force by distance.

In this case, we must sum the works of the force applied by the box and the friction force that also acts on the box.

The friction force is defined as the product of the normal force by the coefficient of friction.

f = N*μ

where:

N = normal force = m*g [N] (units of Newtons)

m = mass = 72 [kg]

g = gravity acceleration = 9.81 [m/s²]

f = friction force [N]

μ = friction coefficient = 0.21

f = 72*9.81*0.21

f = 148.32 [N]

Now the total work:

Wt = WF - Wf

where:

Wt = total work [J] (units of Joules)

WF = work by the pushing force [J]

Wf = work done by the friction force [J]

Wt = (160*2.3) - (148.32*2.3)

Wt = 26.84 [N]

Note: The friction force exerts a negative work, because this force is acting in opposite direction to the movement, therefore the negative sign.

3 0
3 years ago
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