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Ca + H₃PO₄ → Ca₃(PO₄)₂ + H₂
Balance PO₄.
1 on the left, 2 on the right. Add a coefficient of 2 in front of H₃PO₄.
Ca + 2H₃PO₄ → Ca₃(PO₄)₂ + H₂
Balance H.
6 on the left, 2 on the right. Add a coefficient of 3 in front of H₂.
Ca + 2H₃PO₄ → Ca₃(PO₄)₂ + 3H₂
Balance Ca.
1 on the right, 3 on the right. Add a coefficient of 3 in front of Ca.
3Ca + 2H₃PO₄ → Ca₃(PO₄)₂ + 3H₂
Our final balanced equation:
3Ca + 2H₃PO₄ → Ca₃(PO₄)₂ + 3H₂
Hope this helps!
Answers:
<span>Answer 1: 10.03 g of siver metal can be formed.</span>
Answer 2: 3.11 g of Co are left over.
Work:
1) Unbalanced chemical equation (given):
<span>Co + AgNO3 → Co(NO3)2 + Ag
2) Balanced chemical equation
</span>
<span>Co + 2AgNO3 → Co(NO3)2 + 2Ag
3) mole ratios
1 mol Co : 2 mole AgNO3 : 1 mol Co(NO3)2 : 2 mol Ag
4) Convert the masses in grams of the reactants into number of moles
4.1) 5.85 grams of Co
# moles = mass in grams / atomic mass
atomic mass of Co = 58.933 g/mol
# moles Co = 5.85 g / 58.933 g/mol = 0.0993 mol
4.2) 15.8 grams of Ag(NO3)
# moles Ag(NO3) = mass in grams / molar mass
molar mass AgNO3 = 169.87 g/mol
# moles Ag(NO3) = 15.8 g / 169.87 g/mol = 0.0930 mol
5) Limiting reactant
Given the mole ratio 1 mol Co : 2 mol Ag(NO3) you can conclude that there is not enough Ag(NO3) to make all the Co react.
That means that Ag(NO3) is the limiting reactant, which means that it will be consumed completely, whilce Co is the excess reactant.
6) Product formed.
Use this proportion:
2 mol Ag(NO3) 0.0930mol Ag(NO3)
--------------------- = ---------------------------
2 mol Ag x
=> x = 0.0930 mol
Convert 0.0930 mol Ag to grams:
mass Ag = # moles * atomic mass = 0.0930 mol * 107.868 g/mol = 10.03 g
Answer 1: 10.03 g of siver metal can be formed.
6) Excess reactant left over
1 mol Co x
----------------------- = ----------------------------
2 mole Ag(NO3) 0.0930 mol Ag(NO3)
=> x = 0.0930 / 2 mol Co = 0.0465 mol Co reacted
Excess = 0.0993 mol - 0.0465 mol = 0.0528 mol
Convert to grams:
0.0528 mol * 58.933 g/mol = 3.11 g
Answer 2: 3.11 g of Co are left over.
</span>
The answer is decomposition
Answer:
CaC₂(s) + 2H₂O(l) --> C₂H₂(g) + Ca(OH)₂(aq)
Explanation:
We are given;
The unbalanced equation;
CaC₂(s) + 2H₂O(l) --> C₂H₂(g) + Ca(OH)₂(aq)
We are required to balance the equation;
- We need to know that balancing of chemical equations involves putting the appropriate coefficients on reactants and products to ensure equal number of atoms of each element on both sides of the equation.
- Balancing of chemical equations is a try and error method of making sure that the law of conversation of mass in chemical equations is obeyed.
- In our case, the appropriate coefficients will be, 1, 2, 1, 1
Therefore;
The balanced equation will be;
CaC₂(s) + 2H₂O(l) --> C₂H₂(g) + Ca(OH)₂(aq)
Answer:
Column A 
Column B
1. CaS Calcium Sulfide
2. CaSO₄ Calcium sulfate
3. CaSO₃ Calcium sulfite
Explanation:
1) Calcium sulfide is a compound formed between calcium, Ca, and sulfur, S, with a chemical formula of CaS. It forms cubic crystals similar to rock salt, and smells like rotten eggs
2) Calcium sulfate is a chemical compound consisting of calcium, Ca, and sulfate SO₄. It is found in nature in the hydrated form as the mineral gypsum
3)Calcium sulfite is a chemical compound formed between calcium, Ca and sulfite, SO₃ used to treat water and preserve food.
