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matrenka [14]
3 years ago
12

¿Cuáles son ejemplos de elementos químicos que pertenecen al grupo de los gases nobles o gases raros?

Chemistry
1 answer:
Aliun [14]3 years ago
5 0

Answer:

traducir al español esa es la respuesta

自分の仕事をする

Explanation:

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antiseptic1488 [7]

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3 years ago
Which compound contains both sigma and pi bonds
Misha Larkins [42]
Any compound with multiple covalent bonds
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3 years ago
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When lightning strikes, nitrogen molecules, n2, and oxygen molecules, o2, in the air react to form nitrates, no3, which come dow
faltersainse [42]
The reaction for what was describe in the problem is:

N₂ + 3 O₂ --> 2 NO₃

The reactants involved are nitrogen and oxygen gas. From the word itself, oxygen is an oxidizing agent. <em>Therefore, this reaction is an oxidation reaction due to the presence of the oxidizing agent.</em>
4 0
3 years ago
HELP
tatiyna

Answer:

Bi (Bismuth)

Ag (Silver)

Li (Lithium)

Explanation:

Xe (Xenon) and I (Iodine) are non-metals. They cannot from a metallic bond because metallic bonds are bonds between metals only.

7 0
2 years ago
Nitrogen and hydrogen combine at a high temperature, in the presence of a catalyst, to produce ammonia. N 2 ( g ) + 3 H 2 ( g )
Kisachek [45]

Answer:

After complete reaction, 0.280 moles of ammonia are produced

Explanation:

Step 1: Data given

Number of moles N2 = 0.140 moles

Number of moles H2 = 0.434 moles

Step 2: The balanced equation

N2(g) + 3H2 (g) ⟶ 2NH3 (g)

Step 3: Calculate the limiting reactant

For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

N2 is the limiting reactant. It will completely be consumed (0.140 moles).

H2 is in excess. There will react 3*0.140 = 0.420 moles

There will remain 0.434 - 0.420 = 0.014 moles

Step 4: Calculate moles NH3

For 0.140 moles N2 we'll have 2*0.140 = 0.280 moles NH3

After complete reaction, 0.280 moles of ammonia are produced

5 0
3 years ago
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