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Phantasy [73]
3 years ago
7

How many of the zeros in the measurement 0.050060 are significant

Chemistry
2 answers:
Feliz [49]3 years ago
6 0
I think 3 of them are its been 1 half years since ive done this i dont take chemistry anymore
earnstyle [38]3 years ago
6 0
3 of them are significant. Two are sandwiched by nonzero significant numbers and since there is a decimal in the number, the zero on the end is also significant
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What is the partial pressure of 0.50 mol Ne gas combined with 1.20 mol Kr gas at a final pressure of 730 torr?
WARRIOR [948]
  The partial pressure  of 0.50  Ne  gas    is   214.71  torr


      calculation

 the partial   pressure  of Ne  = moles  of Ne/total moles  x  final  pressure

 
find  the total  moles  of the air mixture  

that is moles of   Ne  +  moles of K=  0.50 + 1.20  =  1.70 moles
  

The partial  pressure  is therefore =   0.50 /1.70  x  730  =  214.71  torr
   
8 0
3 years ago
Read 2 more answers
Friction is the force that occurs when: A. one object attracts or repels another. B. one object is rubbing against another. C. o
AlladinOne [14]

Answer:

b i think. hope im not wrong

4 0
3 years ago
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Due to the small and highly electronegative nature of fluorine, the oxyacids of the this element are much less common and less s
steposvetlana [31]
We are told we have an oxyacid of the formula HOFO. We will assume the atoms are in this order and will draw a proper lewis structure for this compound by first drawing bonds between each of the 4 atoms and then place the remaining electron pairs on each atom:
      ..    ..    ..
H - O - F - O:
      ··   ··    ··
We can calculate the formal charge of an atom using the following formula:

Formal charge = [# of valence electrons] - [# of non-bonded electrons + # of bonds]

H: Formal charge = [1]-[0+1] = 0

O: Formal charge = [6]-[4+2] = 0

F: Formal charge = [7]-[4+2] = +1

O: Formal charge = [6]-[6+1] = -1

As we can see the overall charge of the molecule is neutral since the fluorine as a +1 charge and the oxygen a -1 charge.
4 0
3 years ago
If you start with 4.3 moles of NH3, how many moles of NANH2 can be produced
mash [69]

Explanation:

Mole ratio of NH3 to NaNH2 = 2 : 2.

Moles of NaNH2 produced

= 4.3mol * (2/2) = 4.3mol.

4 0
2 years ago
2. Calculate the mass of K in 90g of KOH​
ValentinkaMS [17]

KOH = 90g

KOH = 57 g/mol

K = 40g/mol

57g/mol contains 90 g

40g/mol will contain?

= 63.15 g

The mass of K is 63.15g

8 0
2 years ago
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