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Phantasy [73]
3 years ago
7

How many of the zeros in the measurement 0.050060 are significant

Chemistry
2 answers:
Feliz [49]3 years ago
6 0
I think 3 of them are its been 1 half years since ive done this i dont take chemistry anymore
earnstyle [38]3 years ago
6 0
3 of them are significant. Two are sandwiched by nonzero significant numbers and since there is a decimal in the number, the zero on the end is also significant
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Please help me i keep getting this wrong :(
solmaris [256]
A) <span>A chandelier has been hanging in the kitchen for years
B) </span><span>A log floats on top of the lake
C) </span><span>You place your book on the top of a flat table

Those are the answers. In each case, there is always a force that balances the weight of the object and keeps them in a static equilibrium. Tension, Buoyancy and Normal force.</span>
7 0
3 years ago
A 5.0 milliliter sample of a substance has a mass of 12.5 grams. What is the mass of a 100 milliliter sample of the same substan
exis [7]

Answer:

It sould be 250 grams

Explanation:

4 0
2 years ago
The combustion of 0.570 g of benzoic acid (ΔHcomb = 3,228 kJ/mol; MW = 122.12 g/mol) in a bomb calorimeter increased the tempera
torisob [31]

Answer:

The temperature change from the combustion of the glucose is 6.097°C.

Explanation:

Benzoic acid;

Enthaply of combustion of benzoic acid = 3,228 kJ/mol

Mass of benzoic acid = 0.570 g

Moles of benzoic acid = \frac{0.570 g}{122.12 g/mol}=0.004667 mol

Energy released by 0.004667 moles of benzoic acid on combustion:

Q=3,228 kJ/mol \times 0.004667 mol=15.0668 kJ=15,066.8 J

Heat capacity of the calorimeter = C

Change in temperature of the calorimeter = ΔT = 2.053°C

Q=C\times \Delta T

15,066.8 J=C\times 2.053^oC

C=7,338.92 J/^oC

Glucose:

Enthaply of combustion of glucose= 2,780 kJ/mol.

Mass of glucose=2.900 g

Moles of glucose = \frac{2.900 g}{180.16 g/mol}=0.016097 mol

Energy released by the 0.016097 moles of calorimeter  combustion:

Q'=2,780 kJ/mol \times 0.016097 mol=44.7491 kJ=44,749.1 J

Heat capacity of the calorimeter = C (calculated above)

Change in temperature of the calorimeter on combustion of glucose = ΔT'

Q'=C\times \Delta T'

44,749.1 J=7,338.92 J/^oC\times \Delta T'

\Delta T'=6.097^oC

The temperature change from the combustion of the glucose is 6.097°C.

6 0
2 years ago
What is wrong with this model of the atom.
sp2606 [1]

Answer:

A. The neutrons and electrons are in the wrong place.

Explanation:

The atom's nucleus contains both protons and neutrons, whilst the electrons are arranged in shells around the nucleus.

8 0
2 years ago
How does the strength of a metallic bond compared to other types of bonds?
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While metallic bonds have the strong electrostatic force of attractions between the cation or atoms and the delocalized electrons in the geometrical arrangement of the two metals. ... Metallic bonds are malleable and ductile, while covalent bonds and ionic bonds non-malleable and non-ductile.

7 0
3 years ago
Read 2 more answers
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