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3 years ago

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A 65-cm segment of conducting wire carries a current of 0.35 A. The wire is placed in a uniform magnetic field that has a magnit

ude of 1.24 T. What is the angle between the wire segment and the magnetic field if the force on the wire is 0.26 N

2 answers:

Artyom0805 [142]3 years ago

8 0

Answer: The angle between the wire segment and the magnetic field 66.42°

Explanation:

Please see the attachment below

Setler [38]3 years ago

8 0

Answer:

67.17°

Explanation:

From the question,

F = BILsinФ............. Equation 1

Where F = force on the wire, B = magnetic field, I = current carried by the wire, L = length of the wire, Ф = angle between the wire segment and the magnetic field.

make Ф the subject of the equation

Ф =sin⁻¹ (F/BIL)............... Equation 2

Given; F = 0.26 N, B = 1.24, I = 0.35 A, L = 65 cm = 0.65 m

Substitute into equation 2

Ф = sin⁻¹[0.26/(1.24×0.35×0.65)]

Ф = sin⁻¹(0.26/0.2821)

Ф = sin⁻¹(0.9217)

Ф = 67.17°

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Explanation:

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3 years ago

Students in an introductory physics lab are performing an experiment with a parallel-plate capacitor made of two circular alumin

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Answer:

$\rm 9.186\times 10^{-7}\ C.$

Explanation:

<u>Given:</u>

Diameter of the plates of the capacitor, D = 21 cm = 0.21 m.
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When the dimensions of the plate of the capacitor is comparatively much larger than the distance of separation between the plates, then, according to the Gauss' law of electrostatics, the value of the electric field strength in the region between the plates of the capacitor is given by

$\rm E=\dfrac{\sigma}{\epsilon_o}.$

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For the minimum value of electric field that produces spark,

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3 years ago

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Explanation:

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Using Snell's law for red light as :

$n_1\sin\theta_1=n_2\sin\theta_2\\\\\theta_2=\sin^{-1}((\dfrac{n_2}{n_1})\sin\theta_1)\\\\\theta_2=\sin^{-1}((\dfrac{1}{1.4561})\sin(80))\\\\\theta_2=42.555$

Again using Snell's law for blue light as :

$n_1\sin\theta_1=n_2\sin\theta'_2\\\\\theta'_2=\sin^{-1}((\dfrac{n_2}{n_1})\sin\theta_1)\\\\\theta'_2=\sin^{-1}((\dfrac{1}{1.4636 })\sin(80))\\\\\theta'_2=42.283$

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3 years ago