4 + -1 = 3
Or -1 - 4 = -5
I would put 3.
Answer:
7) a= 20
8) m= 5
9)n = 5
10) b = 8
Step-by-step explanation:
7) 18+2=-2+2+a
>> 20 = a >> a = 20
18 + 2 = 20 so that isolates the variable leaving a = 20
8) -7+12 = m -12+12
>>> 5 = m >> m = 5
-7 + 12 = 5 so that again isolates the variable leaving m = 5
9) <u>-8(7</u> + <u>7n</u>) = -336
>> -56+56 + -56n = -336+56
>>> -56n/-56 = -280/-56
>>>> n = 5
use distributive property, cancel out necessary numbers, isolate the variable. leaving n = 5.
10) -140 = <u>-7(-4 </u>+ <u>3b)</u>
>> -140 = 28 - 21b >> -140-28 = -21b +28-28 ( flipped the numbers)
>>> -168/-21 = -21b /-21
>>>> 8 = b >> b =8
Hope it helps!
Answer:
it looks like its all right to me
Step-by-step explanation:
Answer:
69.14% probability that the diameter of a selected bearing is greater than 84 millimeters
Step-by-step explanation:
According to the Question,
Given That, The diameters of ball bearings are distributed normally. The mean diameter is 87 millimeters and the standard deviation is 6 millimeters. Find the probability that the diameter of a selected bearing is greater than 84 millimeters.
- In a set with mean and standard deviation, the Z score of a measure X is given by Z = (X-μ)/σ
we have μ=87 , σ=6 & X=84
- Find the probability that the diameter of a selected bearing is greater than 84 millimeters
This is 1 subtracted by the p-value of Z when X = 84.
So, Z = (84-87)/6
Z = -3/6
Z = -0.5 has a p-value of 0.30854.
⇒1 - 0.30854 = 0.69146
- 0.69146 = 69.14% probability that the diameter of a selected bearing is greater than 84 millimeters.
Note- (The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X)
Answer:
I think it may be 120 cm
Step-by-step explanation:
A F is 13 using pythagorean theorem on triangle CED and applying the hypotenuse length to A F.
ABC is similar to triangle CED and is dilated by a factor of 3 so the base is 36.
using pythagorean theorem on triangle ABC gets the hypotenuse length of 39 which can be applied to FE
add all the values together
39 + 13 + 15 + 36 +12 +5 = 120
