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4 years ago

How do you write a improper fraction a mixed number if it's a negative

Mathematics

1 answer:

Nookie1986 [14]4 years ago

8 0

You simply do it the same way as a positive number, just with a negative sign in front :)

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Which answers are elements of the solution set of the inequality ? check all that apply

jasenka [17]

First, transpose the constants to the right side just like an ordinary equation, but leave the inequality sign as it is. That becomes

x - 72 > -96
x > -96 + 72
x > -24

Thus, just check among the choices which are greater than -24. The answers would be D and E.

4 0

4 years ago

I=prt(interest=principal.rate.time) solve for p

Black_prince [1.1K]

I = PRT/100
100I = PRT
P= 100I÷RT
P = 100I/RT

7 0

4 years ago

Read 2 more answers

Which number line represents the solution set for the inequality - 2x24?

s2008m [1.1K]

Step-by-step explanation:

maybe the second option

5 0

3 years ago

Which of the following could be the ratio of the length of the longer leg of a 30 60 90 triangle to the length of its hypotenuse

yan [13]

For 30 60 90 triangles, the ratio of the side lengths is
$\frac{1}{2} : \frac{ \sqrt{3} }{2} :1$
where the first is the shorter leg, the second is the longer leg, and the third is the hypotenuse (the longest side that doesn't form a 90 degree angle)

so the ratio of the longer leg to the hypotenuse is $\frac{ \sqrt{3} }{2} :1$
or
 $\frac{ \frac{ \sqrt{3} }{2} }{1}$
which equals $\frac{ \sqrt{3} }{2}$

6 0

3 years ago

Which of the following is a true polynomial identity?

velikii [3]

Answer:

see below

Step-by-step explanation:

When in doubt, you can always multiply them out to see .

The expression a^6 + b^6 can be treated as the sum of cubes, which factors as ...

p^3 + q^3 = (p +q)(p^2 -pq +q^2)

In this case, you have p=a^2 and q=b^2, so the factorization is ...

a^6 +b^6 = (a^2 +b^2)((a^2)^2 -(a^2)(b^2) +(b^2)^2)

a^6 +b^6 = (a^2 +b^2)(a^4 -a^2b^2 +b^4) . . . . . . matches choice D

The expression a^6 -b^6 can be treated either as the difference of cubes, or as the difference of squares. In the former case, its factorization would be ...

a^6 -b^6 = (a^2 -b^2)(a^4 +a^2b^2 +b^4) . . . . . . matches no offering

In the latter case, its factorization could be any of ...

a^6 -b^6 = (a^3 -b^3)(a^3 +b^3)

a^6 -b^6 = (a^3 -b^3)(a +b)(a^2 -ab +b^2) . . . . . . . . . . . matches no offering

a^6 -b^6 = (a -b)(a^2 +ab +b^2)(a +b)(a^2 -ab +b^2) . . . matches no offering

a^6 -b^6 = (a^2 -b^2)(a^2 +ab +b^2)(a^2 -ab +b^2) . . . matches no offering

8 0

3 years ago