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givi [52]
3 years ago
8

Transverse waves are sent along a 5.00-m-long string with a speed of 30.00 m/s. The string is under a tension of 10.00 N. What i

s the mass of the string

Physics
1 answer:
Kipish [7]3 years ago
3 0

Answer:

0.055 kg

Explanation:

Given that

Length of the string, l = 5 m

Speed of the wave, v = 30 m/s

Tension on the string, F(t) = 10N

From the formula written in the attachment, we have

v = velocity of the wave, in m/s

F(t) = Tension on the string, in N

U = Mass per length of the string, in kg/m

m = Mass of the string, in kg

l = Length of the string, in m

See attachment for the calculation

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Nastasia [14]

Answer:

D. Molecules of a gas slow down and change to a liquid state.

Explanation:

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4 0
3 years ago
In physics, why would an equation like y=mx+b be plotted as a straight line rather than as a parabola, as is done in math?
notka56 [123]

Answer:

Explanation:

In Both Physics and Math

y=mx+b is plotted as straight line where

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b=intercept on Y-axis

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Math is a tool to solve Physics problems so equations are same in math and physics

3 0
2 years ago
A steady electric current flows through a wire. If 9.0 C of charge passes a particular spot in the wire in a time period of 2.0
defon

1) Current: 4.5 A

2) Time taken: 4.7 s

Explanation:

1)

The electric current intensity is defined as the rate at which charge flows in a conductor; mathematically:

I=\frac{q}{t}

where

I is the current

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For the wire in this problem, we have

q = 9.0 C is the amount of charge

t = 2.0 s is the time interval

Solving for I, we find the current:

I=\frac{9.0}{2.0}=4.5 A

2)

To solve this problem, we can use again the same formula

I=\frac{q}{t}

where

I is the current

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In this problem, we have:

I = 3.0 A (current)

q = 14.0 C (charge)

Therefore, the time taken for the charge to move past a particular spot in the wire is

t=\frac{q}{I}=\frac{14.0}{3.0}=4.7 s

Learn more about electric current:

brainly.com/question/4438943

brainly.com/question/10597501

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8 0
3 years ago
A positive charge of 1 µC is taken from points A & B such that VA-VB = 100 V. Then the
Lunna [17]

Explanation:

It is given that,

Let Charge of 1\ \mu C is taken from points A & B such that V_A-V_B=1000\ V.

We need to find the energy of charge. Electric potential is defined as the work done per unit of electric charge. So,

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4 0
2 years ago
A student says that a speed of 50 m/s is faster than a speed of 140 km/h because the number is bigger. What would you say to the
ladessa [460]

The units are not consistent - 1 m/s is not the same as 1 km/h.

First thing to do would be to convert from one unit of speed to the other, say km/h to m/s. There are 1000 meters (m) for every kilometer (km) and 3600 seconds (s) for every hour (h), so

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4 0
3 years ago
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