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givi [52]
4 years ago
8

Transverse waves are sent along a 5.00-m-long string with a speed of 30.00 m/s. The string is under a tension of 10.00 N. What i

s the mass of the string

Physics
1 answer:
Kipish [7]4 years ago
3 0

Answer:

0.055 kg

Explanation:

Given that

Length of the string, l = 5 m

Speed of the wave, v = 30 m/s

Tension on the string, F(t) = 10N

From the formula written in the attachment, we have

v = velocity of the wave, in m/s

F(t) = Tension on the string, in N

U = Mass per length of the string, in kg/m

m = Mass of the string, in kg

l = Length of the string, in m

See attachment for the calculation

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Answer:

See the explanation below.

Explanation:

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We see that for the bar size of 100G, the energy value is 483 [kcal].

We can see that the energy depends on the size of the chocolate bar.

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What is the difference between atomic structure and crystal structure?
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A proton is moving toward a second, stationary proton. What happens as the protons get closer?
MatroZZZ [7]

Answer:

A. Kinetic energy is converted to electric potential energy, and the proton moves more slowly.

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Two protons according to coulombs law will repel each other with an electrostatic force because they both have similar charges. This will increase their electric potential energy of both of them.

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5 0
3 years ago
Metal sphere 1 has a positive charge of 7.00 nc . metal sphere 2, which is twice the diameter of sphere 1, is initially uncharge
MariettaO [177]

Answer:

2.33 nC, 4.67 nC

Explanation:

when the two spheres are connected through the wire, the total charge (Q=7.00 nC) re-distribute to the two sphere in such a way that the two spheres are at same potential:

V_1 = V_2 (1)

Keeping in mind the relationship between charge, voltage and capacitance:

C=\frac{Q}{V}

we can re-write (1) as

\frac{Q_1}{C_1}=\frac{Q_2}{C_2} (2)

where:

Q1, Q2 are the charges on the two spheres

C1, C2 are the capacitances of the two spheres

The capacitance of a sphere is given by

C=4 \pi \epsilon_0 R

where R is the radius of the sphere. Substituting this into (2), we find

\frac{Q_1}{4 \pi \epsilon_0 R_1}=\frac{Q_2}{4 \pi \epsilon_0 R_2} (3)

we also know that sphere 2 has twice the diameter of sphere 1, so the radius of sphere 2 is twice the radius of sphere 1:

R_2 = 2R_1

So the eq.(3) becomes

\frac{Q_1}{4 \pi \epsilon_0 R_1}=\frac{Q_2}{4 \pi \epsilon_0 2R_1}

And re-arranging it we find:

Q_2 = 2Q_1

And since we know that the total charge is

Q_1 + Q_2 = 7.00 nC

we find

Q_1 = 2.33 nC\\Q_2 = 4.67 nC

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A helicopter flying horizontally at a height H with a speed v0needs to drop a supply capsule to a point P . Assume the capsule h
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L = V0 x t
L = V0 x (2H/g)^1/2
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