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3 years ago

A kind of variable that a researcher purposely changes in investigation is

Physics

1 answer:

Ugo [173]3 years ago

3 0

Answer:

independent variable

Explanation:

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Which inference about Arthur is supported by the text?

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In order for electrical current to flow through a solid, _____. the solid must have electrons the electrons in the solid must be

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2 years ago

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Light from a laser with wavelength 400 nm passed through two small openings and produces an interference pattern on a screen 1 m

alexira [117]

To solve this problem we will apply the concepts related to destructive interference from double-slit experiments. For this purpose we will define the path difference as,

$\text{Path difference}= dsin\theta = (2n-1)\frac{\lambda}{2}$

Here,

$\lambda$ = Wavelength

$\theta$ = Angle when occurs the interference point of destructive interference

Our values are given as,

$\text{Wavelength} = \lambda = 400nm = 4*10^{-7}m$

$\text{Distance of Screen} = D = 1m$

Using the previous expression we have,

$d \times \theta = \frac{\lambda}{2}$

$d \times (0.1) = \frac{4*10^{-7}}{2}$

$d = 2*10^{-6} m$

$d = 2\mu m$ $d = 2\mu m$

Therefore the distance between the two openings is $2\mu m$

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3 years ago

What type of motion does an object have if it is falling with terminal velocity ?

Arte-miy333 [17]

Answer:

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3 years ago

A satellite in geostationary orbit is used to transmit data via electromagnetic radiation. The satellite is at a height of 35,00

Nutka1998 [239]

Answer:

$6.99535\times 10^{-6}\ V/m$

Explanation:

P = Power Output = 1000 W

r = Radius = 35000000 m

$\epsilon_0$ = Permittivity of free space = $8.85\times 10^{-12}\ F/m$

c = Speed of light = $3\times 10^8\ m/s$

Intensity of Electric radiation is given by

$I=\dfrac{P}{A}\\\Rightarrow I=\dfrac{P}{4\pi r^2}\\\Rightarrow I=\dfrac{1000}{4\pi\times 35000000^2}\ W/m^2$

Intensity of Electric radiation is given by

$I=\dfrac{1}{2}c\epsilon_0E_0\\\Rightarrow E_0=\sqrt{\dfrac{2I}{c\epsilon_0}}\\\Rightarrow E_0=\sqrt{\dfrac{2\times \dfrac{1000}{4\pi\times 35000000^2}}{3\times 10^8\times 8.85\times 10^{-12}}}\\\Rightarrow E_0=6.99535\times 10^{-6}\ V/m$

The amplitude of the electric field vector is $6.99535\times 10^{-6}\ V/m$

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