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elixir [45]
3 years ago
7

Is there a link between number of bulbs and current drawn from the power pack?

Physics
1 answer:
Maurinko [17]3 years ago
5 0

Answer:

Yes, there a link between number of bulbs and current drawn from the power pack.

Explanation:

In an Electrical circuit, we have resistors present in that circuit. These resistors can be connected in two ways.

a) Series connection

b) Parallel connection

There is a link or a relationship between number of bulbs and the current drawn from the power pack. This is because the number of bulbs is equivalent to or equal to the number of resistors.

Hence,

a) In a series connection, the link or relationship between the number of bulbs(resistors) is as the number of light bulbs increases, the current in the power pack (circuit) decreases.

b) In a parallel connection, the link or relationship between the number of bulbs(resistors) is as the number of light bulbs increases, the current in the power pack (circuit) increases.

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A probe from earth, with a mass of 106 kg, is in orbit around planet Pud in another solar system. Pud has a radius of 106 m and
DedPeter [7]

Answer:

The acceleration due to gravity in planet Pud is of 9345.7m/s²

Explanation:

Since the probe is describing a circular motion around planet Pud, its centripetal acceleration is given by the formula:

a_c=\frac{v^{2}}{R}

Assuming there is no other external forces acting on the probe in the centripetal direction, we have that

a_c=g_{Pud}=\frac{v^{2}}{R}

Before we plug in the values, we have to convert the speed from km/s to m/s:

1\frac{km}{s} =1000\frac{m}{s}

Finally, using the given values, we can compute g_{Pud}:

g_{Pud}=\frac{(1000\frac{m}{s}) ^{2} }{107m}= 9345.7\frac{m}{s^{2}}

In words, the acceleration due to gravity in planet Pud is of 9345.7m/s²

6 0
3 years ago
A U-shaped tube open to the air at both ends contains some mercury. A quantity of water is carefully poured into the left arm of
Ad libitum [116K]

Answer:

Explanation:

a ) gauge pressure will be due to water column of length 15 cm .

pressure = h d g , h is height of column , d is density of column and g is gravitational acceleration .

= .15 x 10³ x 9.8

= 1470 Pa .

b )

Let due of weight of water column , mercury level in left column goes down by distance h . The level of mercury in right column will rise by the same distance ie by distance h .

So mercury column of 2h height is balancing the water column of height 15 cm

2h x 13.6 x 10³ x g = .15 x 10³ x g

h = .15 / (2 x 13.6)

= .55 x 10⁻² m

= . 55 cm

Difference of height of water column and mercury column

= 15 - 2 x .55 cm

= 13.9 cm .

7 0
3 years ago
Remembering that Force = mass x acceleration. A Football player kicks a ball with a mass of 0.42 kg. The average acceleration of
Anna35 [415]

B) 6.22 N

<em>Is your answer hun! have a great day:3</em>

6 0
3 years ago
Is retractable measuring tape a simple machine?
deff fn [24]

Answer:

A simple machine is a device that multiply an applied force by the use of the mechanical advantage built into the machine. Therefore, a simple machine changes the direction in which the applied force acts or the magnitude of the applied force, or both in order to do work

A retractable measuring tape is a device used for length measurement such that the direction of the applied force is reversed during retraction, while the magnitude of the output force is constant and dependent on the coil in the measuring

Therefore, the measuring tape does not have a constant mechanical advantage or act as a force multiplier, and therefore;

It is not a simple machine

Explanation:

5 0
3 years ago
A 450.0 kg boat experiences two simultaneous forces. The motor exerts a force of 100.0 N to accelerate the boat forward, while a
Cerrena [4.2K]

Answer:

The  drag force is D = 40.15 \  N

Explanation:

From the question we are told that

  The mass is  m =  450.0  \ kg

  The acceleration a  = 0.133 m/s^2

The force due to the motor is  F_m  =  100 \  N

Generally the net force acting on the boat is mathematically represented as

    F  =  m * a

=>  F  =    450.0 * 0.1330

=>  F = 59.85 \ N

Generally the drag force acting on the boat is mathematically represented as

     D =  F_m  -F

=>  D =  100 - 59.85

=>   D = 40.15 \  N

 

7 0
3 years ago
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