All categories

3 years ago

Is there a link between number of bulbs and current drawn from the power pack?

Physics

1 answer:

Maurinko [17]3 years ago

5 0

Answer:

Yes, there a link between number of bulbs and current drawn from the power pack.

Explanation:

In an Electrical circuit, we have resistors present in that circuit. These resistors can be connected in two ways.

a) Series connection

b) Parallel connection

There is a link or a relationship between number of bulbs and the current drawn from the power pack. This is because the number of bulbs is equivalent to or equal to the number of resistors.

Hence,

a) In a series connection, the link or relationship between the number of bulbs(resistors) is as the number of light bulbs increases, the current in the power pack (circuit) decreases.

b) In a parallel connection, the link or relationship between the number of bulbs(resistors) is as the number of light bulbs increases, the current in the power pack (circuit) increases.

You might be interested in

8. Two forces of 10 N and 30 N are applied to a 10 kg box. Find (1) the box’s acceleration when both forces point due east and (

love history [14]

(1) acceleration, a = 4 m/ $s^{2}$ (2) acceleration of 10 N, $a_{1}$ = 1 m/ $s^{2}$ and acceleration of 30 N, $a_{2}$ = 3 m/ $s^{2}$

Explanation:

Here, the acceleration of the object could be found using the equation derived in the second law of motion. The equation is given as, F = ma where m is the acceleration of the object, m is the mass of the object and F is the applied on the object.
Let $a_{1}$ be the acceleration for force 10 N, to find acceleration rearrange the equation to a = $\frac{F}{m}$ . When we substitute 10 N force and 10 kg mass of the box in the equation. We will get $a_{1}$ = 1 m/ $s^{2}$

Let $a_{2}$ be the acceleration for force 30 N, to find acceleration rearrange the equation to F = $\frac{F}{m}$ . When we substitute 30 N force and 10 kg mass of the box in the equation. We will get $a_{2}$ = 3 m/ $s^{2}$
To find the combined, just add the force and substitute in the above equation. Hence, a = 4 m/ $s^{2}$

3 0

2 years ago

A mountain climber ascends a mountain to its peak. The peak is 12,470 ft above sea level. The climber then descends 80 ft to mee

o-na [289]

The answer is 12,390 ft.

At first, a climber is at 12,470 ft above sea level. But then, he goes down 80 ft to meet a fellow climber. So, this simply needs to be distracted:
12,470 ft - 80 ft = 12,390 ft
This is the elevation above sea level at which he meet the other climber.

8 0

2 years ago

Building Restoration, Inc. (BRI), enters into a contract to refurbish an old train depot for Casual Dining, Inc., to open as Eat

makkiz [27]

Answer:

Option C

Explanation:

Building Restoration, Inc. (BRI) entered into a contact to refurbish an old train depot for Casual Dining which means it will renovate or redecorate the old train depot for casual dining

In case of refurbishing it will just renovate the old building and will not demolish that building

∴ If BRI completes most of the work promised in the contract, its performance will be reformation

4 0

3 years ago

A person who weighs 625 N is riding a 98-N mountain bike. Suppose that the entire weight of the rider and bike is supported equa

kozerog [31]

Answer:

A = 4.76 x 10⁻⁴ m²

Explanation:

given,

weight of the person = 625 N

weight of the bike = 98 N

Pressure on each Tyre = 7.60 x 10⁵ Pa

Area of contact on each Tyre = ?

total weight of the system = 625 + 98

= 723 N

Let F be the force on both the Tyre

F + F = W

2 F = 723

F = 361.5 N

F = P A

$A = \dfrac{F}{P}$

$A = \dfrac{361.5}{7.60 \times 10^5}$

A = 4.76 x 10⁻⁴ m²

7 0

3 years ago

Do heavier objects fall more slowly than lighter objects?

Alchen [17]

No,Heavier objects weighs more than lighter objects and it falls faster then lighter objects.
Does a meteor fall faster than a little stone?
The meteor is faster.
Wish you happy timez!

5 0

3 years ago