Answer:
The oxidation number of a monatomic (composed of one atom) ion is the same as the charge of the ion. For example, the oxidation numbers of K+, Se2−, and Au3+ are +1, -2, and +3, respectively. The oxidation number of oxygen in most compounds is −2.
Explanation:
The frequency of a wave is the number of wave cycles per second. this quantity is given the symbol ν and has units of s^–1 or hertz.
What is a wave ?
A wave is a dynamic disturbance of one or more quantities that propagates through time. When waves oscillate frequently around an equilibrium value at a certain frequency, they are said to be periodic.
What is a wave cycle ?
The wavelength is the measured distance in meters between two waves' peaks or troughs, which is referred to as a wave cycle. It's crucial to remember that the distance from peak to peak equals the distance from trough to trough. The length of time it takes a wave to complete one cycle is known as the wave's period.
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It’s going 3m/s. If we have 5 seconds to work with then we can find the acceleration by adding speed and how fast it going every second. So like the 7-10-13-16-19 so we go 3m/s faster ever second
Answer:
Ammonia, 
Explanation:
If a Rac variant, in which the residue at position 61 was replaced with an alanine (Rac-61A), was synthesized. Also, Wild-type Rac and Rac-61A were incubated separately with VopC.
In order to obtain data to support that VopC modifies Rac at residue 61, the samples should be analyzed for the presence of Ammonia (
and as such when ammonia is present in the sample containing Wild-type Rac but not in Rac-61A, this simply proves or provide the data to support that VopC modifies Rac at residue 61.
<em>Additionally, deamidation can be defined as the chemical conversion (hydrolysis) of an amide functional group such as glutamine, asparagine, in a polypeptide to another functional group such as glutamic acid or isoaspartic acid respectively by treating it with a strong acid (deamidate, transamidase). </em>
Answer:
fundamental frequency= 20Hz
length= 4.3m
Explanation:
resonating frequencies = 60 Hz,100 Hz,140 Hz
speed of sound =344 m/s
as well behaves as organ pipe with are end closed
only odd harmonics are allowed
, so the vibration will corresponds to n=1,3,5,7....
(2n−1) λ
/4 = l (∵λ
= V/f)
(2n-1) V / 4f = l
(2m-1)/6= (2n-1)/10= (2p-1)/14 =A
The given frequencies happen to be 3rd,5th & 7th harmonics of the fundamental frequency n=20Hz.
Therefore, The fundamental frequency will be 20 Hz because 60 Hz is corresponding 3rd harmonic
In order to find length,
(2n-1) V / 4f = l
= 4.3m
therefore, the well is 4.3m deep