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aleksley [76]
3 years ago
5

What is a prokaryote cell/ eukaryote cell?

Physics
1 answer:
Wewaii [24]3 years ago
8 0
A prokaryote is a microscopic single-celled organism that has neither a distinct nucleus with a membrane nor other specialized organelles. Prokaryotes include the bacteria and cyanobacteria.

A eukaryote is an organism consisting of a cell or cells in which the genetic material is DNA in the form of chromosomes contained within a distinct nucleus. Eukaryotes include all living organisms other than the eubacteria and archaebacteria.
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Your little sister (mass 25 kg) is sitting in her little red wagon (mass 8.5 kg) at rest. You begin pulling her forward, acceler
Nata [24]

Answer:

Your little sister (mass 25.0  ) is sitting in her little red wagon (mass 8.50  at rest. You begin pulling her forward and continue accelerating her with a constant force for 2.35  at the end of which time she's moving at a speed of 1.80  .

(a) Calculate the impulse you imparted to the wagon and its passenger. (b) With what force did you pull on the wagon?

4 0
3 years ago
What is the weight of a 45 kg box?
8_murik_8 [283]
45 kg.Hope it helps! :)
4 0
3 years ago
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What is equal to the kinetic energy of a car with a mass of 0.5t (tonne) if it travels evenly at 70 km/h?
Pavlova-9 [17]

V= 70 km/h = 70 *(1000/3600)= 19.44 m/s

m=0.5 t = 500 kg

Ek=?

Ek=0.5*m*V²

Ek=0.5*500*19.44²

Ek = 94522 J = 94.522 kJ

8 0
3 years ago
If you were to triple the size of the Earth (R = 3R⊕) and double the mass of the Earth (M = 2M⊕), how much would it change the g
EastWind [94]

Answer:

Decreased by a factor of 4.5

Explanation:

"We have Newton formula for attraction force between 2 objects with mass and a distance between them:

F_G = G\frac{M_1M_2}{R^2}

where G =6.67408 × 10^{-11} m^3/kgs^2 is the gravitational constant on Earth. M_1, M_2 are the masses of the object and Earth itself. and R distance between, or the Earth radius.

So when R is tripled and mass is doubled, we have the following ratio of the new gravity over the old ones:

\frac{F_G}{f_g} = \frac{G\frac{M_1M_2}{R^2}}{G\frac{M_1m_2}{r^2}}

\frac{F_G}{f_g} = \frac{\frac{M_2}{R^2}}{\frac{m_2}{r^2}}

\frac{F_G}{f_g} = \frac{M_2}{R^2}\frac{r^2}{m_2}

\frac{F_G}{f_g} = \frac{M_2}{m_2}(\frac{r}{R})^2

Since M_2 = 2m_2 and r = R/3

\frac{F_G}{f_g} = \frac{2}{3^2} = 2/9 = 1/4.5

So gravity would have been decreased by a factor of 4.5  

8 0
3 years ago
A neutral object has:
mars1129 [50]

Answer:

c. Only neutrons.

hope it helps :)

3 0
2 years ago
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