Answer:
15.04 mL
Explanation:
Using Ideal gas equation for same mole of gas as
Given ,
V₁ = 21 L
V₂ = ?
P₁ = 9 atm
P₂ = 15 atm
T₁ = 253 K
T₂ = 302 K
Using above equation as:
Solving for V₂ , we get:
<u>V₂ = 15.04 mL</u>
1. Q=112.8 kJ
2. Q=5.01 kJ
<h3>Further explanation</h3>
The heat required for phase change :
Q = mLf
Lf=latent heat of fusion
- vaporization/condensation
Q = mLv
Lv=latent heat of vaporization
1.
m=50 g=0.05 kg
Lv (water) = 2256 kJ/kg

2.
m=15 g=0.015 kg
Lf for water = 334 kj/kg

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